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PolarNik [594]
3 years ago
6

A quadratic equation is shown below: 4x2 − 12x + 9 = 0

Mathematics
1 answer:
lys-0071 [83]3 years ago
6 0
A)

The discriminant (radicand) is √(b^2-4ac), let us call this "d" for the discriminant.

If:

d<0, there are no real solutions (though there are two imaginary ones)

d=0, there is one real solution

d>0, there are two real solutions.

In this case, d=12^2-4(4)9

d=144-144

d=0

So there is one real solution.

B)

9x^2-30x+25=0

9x^2-15x-15x+25=0

3x(3x-5)-5(3x-5)=0

(3x-5)(3x-5)=0

(3x-5)^2=0

x=5/3

x=1 2/3
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Help! It says that I need to determine If both equations represent lines which are parallel, perpendicular, or none...
12345 [234]
    4x + 2y = 8     (1)
    8x + 4y = -4y  (2)

A) Two lines are parallel if they have the same gradient
       - putting both equations into the gradient- intercept form ( y = mx + c                where m is the gradient)
            (1) 4x + 2y = 8
                          2y = 8 - 4x
                            y = -2x + 4
             
            (2) 8x + 4y = -4y
      <span>                    </span>8x = -4y - 4y
                            y = \frac{-8x}{-8}
                            y = -x
   <span>Thus the gradient of the two equations are different and as such          the two lines are not parallel
</span>
B)  When two lines are perpendicular, the product of their gradient is -1
                   m_{1} * m_{2} = p
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https://www.omnicalculator.com/math/slope

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If abx - 5 = 0, what is x in terms of a and b?
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x=<u />\frac{5}{ab}
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