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AlladinOne [14]
4 years ago
9

Saturated fatty acids are different to unsaturated fatty acids because they ________. Have no C=C double bonds Have short hydrop

hobic tails Exhibit free rotation about the carbon-carbon bonds in the hydrocarbon tail Have an even number of carbon atoms
Chemistry
1 answer:
djverab [1.8K]4 years ago
5 0

Answer:

Have no C=C double bonds

Explanation:

An saturated compound is the one that cannot undergo certain addition reactions like a hydrogenation, which means that they do not have any double or triple bonds. Therefore Unsaturated Fatty acids do have double bonds, they can be monounsaturated (with one C=C bond) like oleic acid, or polyunsaturated (many C=C bonds) like DHA with 6 unsaturations.

Saturated or unsaturated fatty acids can have short or long hydrophobic tail and both categories can have an even number of carbon atoms:

with 14 C : Myristoleic acid (unsaturated) - Myristic acid (saturated)

with 22 C : DHA (unsaturated) - Behenic acid (saturated)

Any single bond C-C can have free rotation, and even though unsaturated fatty acids presents double bonds they also have single bonds in their hydrocarbon tail.

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An acid-base reaction will always produce water and which one of the
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Answer: Option D) Salt

Explanation:

An example of acid-base reaction is

HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

Acid + base → Salt + Water.

Here, water H2O and salt, NaCl are produced.

Usually, the acid, aqeous HCl reacts completely with an appropriate amount of the base, aqueous NaOH to produce salt, aqueous NaCl and water, liquid H2O only, in a process also known as neutralization reaction

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Answer:

Explanation:

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3 years ago
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it is B

Explanation:

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3 years ago
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Answer:

3-bromo-4-ethyl-2,2,5-trimethyloctane.

Explanation:

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Number the carbon chain from 1-8, starting at the end that is closest to a group.  The left side is closest to a group so start from there.

On carbon 2, there are two methyl groups.  On carbon 5, there is one methyl group.  When naming, it will be 2,2,5-trimethyl.

On carbon 3, there is one bromine group.  When naming, it will be 3-bromo.

On carbon 4, there is one ethyl group.  When naming, it will be 4-ethyl.

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The name of the compound is 3-bromo-4-ethyl-2,2,5-trimethyloctane.

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