Answer:
Their isn't your examples but I will give you mine
Freezing, Evaporation and so on.
I think hand picking is best for this case.another method can be done in which first u have melt those candies with marbles.u will hart candy will melt quickly.so,when candies melt ,u will find marbles are still solid but candies are in liquid form .now take a net and purify that solution(candies and marbles).now the candies will pass through net but marbles will stuck in upper net.remove marbles now
Answer:
The answer to your question is 203.8 g
Explanation:
Data
Average atomic mass = ?
Centium-200
Centium-203
Centium-209
Equal amounts
Process
1.- Determine the abundance of each isotope.
If they are in equal amounts in nature, just divide 100 by 3
100/3 = 33.33 % or 0.333
2.- Determine the Average atomic mass
Average atomic mass = Atomic mass 1 x abundance + Atomic mass 2 x
abundance + Atomic mass 3 x abundance
- Substitution
Average atomic mass = 200 x 0.333 + 203 x 0.333 + 209 x 0.333
- Simplification
Average atomic mass = 66.6 + 67.6 + 69.6
Result
Average atomic mass = 203.8 g
Answer: A. is elliptical
B. IS inrregulur C. spiral
Explanation: this should be it
