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nevsk [136]
3 years ago
10

How much centimeters get to 2 meters

Mathematics
2 answers:
gregori [183]3 years ago
5 0
2 meters is equal to 200 centimeters
This is because 100 centimeters is also 1 meter so 200 centimeters is equivalent to 2 meters
zhannawk [14.2K]3 years ago
4 0

Answer:

2meters = 200centimeters

Step-by-step explanation:

multiply 2meters by 100

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The temperature at 6 P.M. was 31 F. By midnight, it had dropped 40 F. What was the temperature at midnight?
aivan3 [116]

Answer:

-9F

Step-by-step explanation:

31F-40F= -9F

all you needed to do was subtract :))

5 0
3 years ago
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in a school election 1/3 of the students vote. there are 655 ballots. find the number of students at the school
Basile [38]

Answer:

45

Step-by-step explanation:

2*23

6 0
3 years ago
HELP PLEASE <br><br> Complete the table given one rule <br><br> Rule: y=4x
I am Lyosha [343]

The rule is that y equals 4 times x.

Whatever value of x you have, multiply it by 4 to find the corresponding y value.

If x = 3, y = 4 * 3 = 12

If x = 4, y = 4 * 4 = 16

If x = 5, y = 4 * 5 = 20

The table looks like this:

x       y

3     12

4      16

5     20

6 0
3 years ago
The Metropolitan Bus Company claims that the mean waiting time for a bus during rush hour is less than 5 minutes. A random sampl
Wewaii [24]

Answer:

Decision is reject the H_0 as There is sufficient evidence to support the claim that the mean time is less then 5 minutes.

Step-by-step explanation:

Consider the provided information.

The mean waiting time for a bus during rush hour is less than 5 minutes.

Thus the null hypothesis is:

H_0: \mu\geq 5

H_1: \mu< 5

A random sample of 20 waiting times has a mean of 3.7 minutes with a standard deviation of 2.1 minutes. At α = 0.01,

Now use the table to find the z value, where α = 0.01,

t_L = -2.3264

The value of n is 20, sample mean is 3.7, population mean is 5 and standard deviation is 2.1.

Now, use the formula: Standardized test statistic for z-scores =t=\frac{\bar x-\mu_0}{{s}/{\sqrt{n} }}.

Substitute the respective values in the above formula.

t=\frac{3.7-5}{{2.1}/{\sqrt{20} }}

t=\frac{-1.3}{0.47}

t=-2.768465115\approx-2.77

As, the test statistic is in the reject interval, so reject H_0

There is sufficient evidence to support the claim that the mean time is less then 5 minutes.

7 0
4 years ago
52/100 in simplest form
ololo11 [35]
0.52 Im pretty sure. Hope this helps!
3 0
4 years ago
Read 2 more answers
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