2. Find the derivative of f (x) = 5x + 9 at x = 2.
A) 9
B) 5
C) 0
D) 10<span><span>
</span><span>f (x) = 5x + 9
</span><span>The first thing we should do in this case is to derive the function.
</span><span>We have then:
</span><span>f '(x) = 5
</span><span>We now evaluate the function for the value of x = 2.
</span><span>We have then:
</span><span> f '(2) = 5
</span><span>Answer:
</span><span> the derivative of f (x) = 5x + 9 at x = 2 is:
</span><span>B) 5
</span><span>3. Find the derivative of f (x) = 8 divided by x at x = -1.
</span><span>4
</span><span>0
</span><span>8
</span><span> -8
</span><span>f (x) = 8 / x
</span><span>The first thing we should do in this case is to derive the function.
</span><span>We have then:
</span><span>f '(x) = ((0 * x) - (1 * 8)) / (x ^ 2)
</span><span> Rewriting we have:
</span><span> f '(x) = -8 / (x ^ 2)
</span><span>We now evaluate the function for the value of x = -1.
</span><span> We have then:
</span><span>f '(- 1) = -8 / ((- 1) ^ 2)
</span><span>f '(- 1) = -8
</span><span>Answer:
</span><span>The derivative of f (x) = 8 divided by x at x = -1 is:
</span><span>-8
</span><span> 4. Find the derivative of f (x) = negative 11 divided by x at x = 9.
</span><span> A) 11 divided by 9
</span><span>B) 81 divided by 11
</span><span>C) 9 divided by 11
</span><span> D) 11 divided by 81
</span><span> f (x) = -11 / x
</span><span>The first thing we should do in this case is to derive the function.
</span><span> We have then:
</span><span>f '(x) = ((0 * x) - (1 * (- 11))) / (x ^ 2)
</span><span>Rewriting we have:
</span><span> f '(x) = 11 / (x ^ 2)
</span><span>We now evaluate the function for the value of x = 9.
</span><span>We have then:
</span><span> f '(9) = 11 / ((9) ^ 2)
</span><span> f '(9) = 11/81
</span><span>Answer:
</span><span>the derivative of f (x) = negative 11 divided by x at x = 9 is:
</span><span>D) 11 divided by 81
</span><span>5. The position of an object at time is given by s (t) = 3 - 4t. </span><span>Find the instantaneous velocity at t = 8 by finding the derivative.
</span><span>s (t) = 3 - 4t
</span><span>For this case, the first thing we must do is derive the given expression.
</span><span>We have then:
</span><span>s' (t) = - 4
</span><span>We evaluate now for t = 8
</span><span> s' (8) = - 4
</span><span>Answer:
</span><span> the instantaneous velocity at t = 8 by finding the derivative is:
</span><span>s' (8) = - 4</span></span>
Answer:
8 °C
Step-by-step explanation:
Step 1: Given data
Initial temperature value (T1): -10 °C
Final temperature value (T2): -2 °C
Step 2: Calculate the change in temperature from the morning to the afternoon
To calculate the change in the temperature, we have to perform the subtraction T2 - T1.
ΔT = T2 - T1 = (-2 °C) - (-10 °C) = -2 °C + 10 °C = 8 °C
The temperature change is positive, meaning that the temperature increased.
Answer: oop i forgot
Step-by-step explanation srry
Answer:
5/6
Step-by-step explanation:
i know that i tolde you i like you o na-na and ohhhhh baby
Answer:
In every 2.5 hours number of sales made by Lydia=10 sales
2.5 hours = 10 sales
Dividing both side by 2.5
In 1 hour = 4 sales
On a particular day
In 2 hours , number of sales made=6 sales
As we have to find number of sales in next 6 hours.
Total number of hours =2+6=8 hours
So, number of sales should be=8×4=32
But in 2 hours , she made 6 sales.
In order to meet his average sale , she should sell →32- 6=26 sales in next 6 hours.