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nadya68 [22]
3 years ago
5

How can you determine the equation that represents this relationship?

Mathematics
2 answers:
shusha [124]3 years ago
7 0

Answer:

FINDING THE EQUATION OF A LINEAR RELATIONSHIP. We can use the points on a graph of a linear relationship to write an equation for the relationship. The equation of a linear relationship is y = mx + b, where m is the rate of change, or slope, and b is the y-intercept (The value of y when x is 0). Example 1 : A handrail runs alongside a stairway. As the horizontal distance from the bottom of the stairway changes, the height of the handrail changes.

SOVA2 [1]3 years ago
3 0
Ans: The equation that represents a proportional relationship, or a line, is y=kx, where k is the constant of proportionality. Use k=yx from either a table or a graph to find k and create the equation. Proportional relationships can be represented by tables, graphs and equations.
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An eraser is in the shape of a triangular prism. Its dimensions are shown in the diagram. What is surface area of the
Colt1911 [192]

Answer:

6000 square millimeters

Step-by-step explanation:

Side length of the slanting side can be calculated using the Pythagorean theorem,

L = sqrt(30^2+40^2) = 50

sufrace area of a triangular prism

= surface area of the end sections + the surface area of the three side faces

= 2*(30*40/2) + 40*(30+40+50)

= 1200 + 4800

= 6000 mm^2

4 0
3 years ago
Read 2 more answers
Can someone pleasw helppppppp meee
Sergio [31]
It would be 2,5, and 6. The mode means the number that is repeating the most. Since 2, 5, and 6 all appear 3 times, that is the mode
6 0
2 years ago
Read 2 more answers
Brian needs to paint a logo using two right triangles. The dimensions of the logo are shown below. What is the difference betwee
solong [7]

Answer:

7.5 cm²

Step-by-step explanation:

Dimensions of the large ∆:

base (b) = 3cm, height (h) = 9cm

Area = 0.5*b*h = 0.5*3*9 = 13.5 cm^2

Dimensions of the small ∆:

base (b) = 2cm, height (h) = 6cm

Area = 0.5*b*h = 0.5*2*6 = 6 cm^2

Difference between the area of the large and the small ∆ = 13.5 - 6 = 7.5 cm²

5 0
2 years ago
The 9th and the 12th term of an arithmetic progression are 50 and 65 respectively. find the common difference
Rzqust [24]

The first term of the arithmetic progression exists at 10 and the common difference is 2.

<h3>How to estimate the common difference of an arithmetic progression?</h3>

let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.

We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula

The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.

9th term = 50

a + 8d = 50 ...............(1)

12th term = 65

a + 11d = 65 ...............(2)

subtract them, (2) - (1), we get

3d = 15

d = 5

If a + 8d = 50 then substitute the value of d = 5, we get

a + 8 * 5 = 50

a + 40 = 50

a = 50 - 40

a = 10.

Therefore, the first term is 10 and the common difference is 2.

To learn more about common differences refer to:

brainly.com/question/1486233

#SPJ4

4 0
2 years ago
Jim had some dimes, quarters, and nickels. First, he counted only the dimes and quarters and found that he had 9 coins. Then, he
Olegator [25]

Answer:

$1.90

Step-by-step explanation:

Represent the numbers of nickels, dimes and quarters by n, d and q.

Then: d + q = 9, or q = 9 - d.

Also, n + d = 10

Lastly, n + d + q = 15.

Let's substitute 9 - d for q in the equation immediately above:

n + d + (9 - d) = 15, or n + 9 = 15.  Then n must be 6.

In summary, Jim has 6 nickels, (10 - 6) dimes and (9 - 4) quarters, or:

                                    6 nickels, 4 dimes and 5 quarters

Thus, he has 5($0.05) + 4($0.10) + 5($0.25), or

                         $0.25   +   $0.40   + $1.25, or          $1.90

7 0
3 years ago
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