A space cushion is a certain amount of distance you keep between u and the car in front of u that allows u to easily maneuver in any condition. The benefit would be : if another driver makes a mistake, ur space cushion gives u time to react.
The solution to the problem is as follows:
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the genaral term is 5Cr(-1)^r 2^r x^(5-2r)
and so need 5-2r = -1 => r = 3
Coeff is then 5C3 (-1)^3 2^3 = -80
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Answer:
The constant force exerted on the ball by the wall is 119.68 N.
Step-by-step explanation:
Consider the provided information.
It is given that the mass of the ball is m = 2.2 kg
The initial velocity of the ball towards left is 7.4 m/s
So the momentum of the ball when it strikes is = 
The final velocity of the ball is -6.2 m/s
So the momentum of the ball when it strikes back is = 
Thus change in moment is: 
The duration of force exerted on the ball t = 0.25 s
Therefore, the constant force exerted on the ball by the wall is:

Hence, the constant force exerted on the ball by the wall is 119.68 N.
Answer(s):
Exact Form: x + 2 y − 3 z = 15 , 2 x − 2 z = 6 , 3 2 3
Mixed Number Form: x + 2 y − 3 z = 15 , 2 x − 2 z = 6 , 3 2 3
Improper Fraction Form: x + 2 y − 3 z = 15 , 2 x − 2 z = 6 , 11 3
Decimal Form: x + 2 y − 3 z = 15 , 2 x − 2 z = 6 , 3. ¯ 6
Hope this helps, have a nice day/night! :D