<h2>f = -5</h2><h3></h3><h3>f(x) = 4x - 9</h3><h3>Add 9 to both sides</h3><h3>f(x) + 9 = 4x</h3><h3>Divide x from both sides</h3><h3>f + 9 = 4</h3><h3>Subtract 9 from both sides</h3><h3>f = -5</h3><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>
Answer:
Our answer is 0.8172
Step-by-step explanation:
P(doubles on a single roll of pair of dice) =(6/36) =1/6
therefore P(in 3 rolls of pair of dice at least one doubles)=1-P(none of roll shows a double)
=1-(1-1/6)3 =91/216
for 12 players this follows binomial distribution with parameter n=12 and p=91/216
probability that at least 4 of the players will get “doubles” at least once =P(X>=4)
=1-(P(X<=3)
=1-((₁₂ C0)×(91/216)⁰(125/216)¹²+(₁₂ C1)×(91/216)¹(125/216)¹¹+(₁₂ C2)×(91/216)²(125/216)¹⁰+(₁₂ C3)×(91/216)³(125/216)⁹)
=1-0.1828
=0.8172
The answer is:<span>
</span><span>
</span><span>= <span><span>2p</span>+<span>10</span></span></span>
Answer:
a(n)= a(n-1) .10
Clearly see the equation
you can do it directly Apply logic
Every n th term is 10 times of previous n-1 th term
That is common ratio an/a(n-1)= 10
So, We have to find 4 th term
So, 4 th term is simply
1st term × (common ratio)^(4-1)
-11( 10)^3
-11000
Thanks
Answer:
13 goats and 23 cows
Step-by-step explanation:
Use x to solve :) it's a hint
