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Viefleur [7K]
3 years ago
7

The class​ ________ is the​ breadth, or​ range, of numbers we plan to put into each class of a frequency distribution using grou

ped quantitative data.
Mathematics
1 answer:
NikAS [45]3 years ago
4 0

Answer:

Width

Step-by-step explanation:

When we have quantitative data it is grouped in classes. There are three ways in which the data can be grouped they are:

Single value grouping where each class has one distinct value.

In Cutpoint grouping is used when the observations have decimal points

In Limit grouping a classes are set based on a specified range of values. Here limit grouping is being done and the range of each class is called width.

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Inverse variation ?
Nookie1986 [14]
<h2>Answer:</h2>

<u>The pressure will be 176 k Pa</u>

<h2>Step-by-step explanation:</h2>

Boyle's law states that the product of volume and pressure gives us a constant value so we can write the expression as

P1V1 = P2V2

By arranging the equation we get

P1V1 / V2 = P2

Putting the values

(132 x 20 ) / 15 = P2

P2 = 176 k Pa

4 0
3 years ago
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I REALLY NEED HELP!
anastassius [24]

\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$3700\\ r=rate\to 4.5\%\to \frac{4.5}{100}\dotfill &0.045\\ t=years\dotfill &7 \end{cases} \\\\\\ A=3700e^{0.045\cdot 7}\implies A=3700e^{0.315}\implies A\approx 5069.96

8 0
3 years ago
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A shopkeeper bought wheat for rs.35000. Due to leakage in the godown 1/7 of the total wheat was spoiled. He sold the good wheat
sladkih [1.3K]
<h2>Question: </h2>

A shopkeeper bought wheat for rs.35000. Due to leakage in the godown 1/7 of the total wheat was spoiled. He sold the good wheat at a gain of 10% and the spoiled when at a loss of 25%. Find his total gain or loss per cent.

Answer:

<h2>5%</h2>

<h2>step by step answer:</h2>

In the question we are given a shopkeeper or bought wheat for Rs. 35000. Now, due to leakage 17 of the total wheat is spoiled. Now, he sold the good wheat at 10% gain and the bad wheat at 25% loss. We need to find the total gain/loss percent.

According to the problem, the total cost of wheat is Rs. 35000.

Now, let us find the cost price of the spoiled wheat.

So, the cost of spoiled wheat is 17×Rs35000 which is equal to Rs. 5000.

Hence, the cost price of spoiled wheat is Rs 5000.

As we know that the spoiled wheat was sold at 25% loss, so we can say that if the cost price is considered as 100% so the selling price is considered as (100−25)% or 75%.

So, we got the selling price of spoiled wheat is 75100×5000=Rs3750

So, the cost price of spoiled wheat is Rs.5000 and selling price of spoiled wheat is Rs.3750.

Now, let us find the cost price of the good wheat.

Now, we will consider the good quality of wheat whose cost price is Rs(35000−5000) which is Rs. 30000.

Hence, the cost price is Rs. 30000.

As we know good quality wheat was sold at 10% gain so we can say that, if the cost price is 100% then the selling price will be (100+10)% or 110% .

Hence, the selling price of good quality wheat is 110100×Rs30000 which is Rs. 33000.

So, the cost price of good quality wheat is Rs. 30000 and selling price is Rs. 33000.

Let us find the total selling price of the wheat that the shopkeeper bought.

Now the total selling price of the wheat is Rs.3750+Rs.30000=Rs.36750.

Hence Profit = Total selling price − Total cost price

profit =Rs.36750−Rs.35000

=Rs.1750

profit %

=profitcost price×100%.

=175035000×100%.

=5%.

<h2>So, total profit is 5%.</h2>
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What is 30,000 expressed in scientific notation?
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Answer:

B

Step-by-step explanation:

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