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Viefleur [7K]
3 years ago
7

The class​ ________ is the​ breadth, or​ range, of numbers we plan to put into each class of a frequency distribution using grou

ped quantitative data.
Mathematics
1 answer:
NikAS [45]3 years ago
4 0

Answer:

Width

Step-by-step explanation:

When we have quantitative data it is grouped in classes. There are three ways in which the data can be grouped they are:

Single value grouping where each class has one distinct value.

In Cutpoint grouping is used when the observations have decimal points

In Limit grouping a classes are set based on a specified range of values. Here limit grouping is being done and the range of each class is called width.

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Jonah finds the length of the sides of the quadrilateral
azamat

Answer: Side BC has a length of square root 10 units

Step-by-step explanation: I just took the test

4 0
4 years ago
What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

     x>2

The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

7 0
3 years ago
The quantity r varies jointly with t and u and inversely with s when t= -12, u= -7, and s= -4, r= -126. Find r when t= -8, u= 8,
vichka [17]

Answer:

r = 64

Step-by-step explanation:

r = (k*t*u)/s

Where,

k = constant of proportionality

t = -12,

u= -7,

s= -4,

r= -126.

r = (k*t*u)/s

-126 = (k*-12*-7)/-4

-126 * -4 = 84k

504 = 84k

k = 504/84

k = 6

Find r when t= -8, u= 8, and s= -6.

r = (k*t*u)/s

= (6*-8*8) / -6

= -384 / -6

= 64

r = 64

6 0
3 years ago
Is the least number to be added to 5607 to get a perfect square. <br> pls add the steps.
daser333 [38]

Answer:

18

Step-by-step explanation:

70^2 = 4900 < 5607 < 6400 = 80^2

so sqrt(5607) is a two-digit number with tenth-digit 7

71^2 = 5041, 72^2 = 5184, 73^2 = 5329, 74^2 = 5476, 75^2 = 5625

so the smallest square bigger than 5607 is 75^2, which is 5625

so the number should ne 5625 - 5607 = 18

8 0
3 years ago
Plz help im so confused
adelina 88 [10]

Answer:

i dont k if my explanation will help or not

Step-by-step explanation:

but it goes through the crosshairs in the 2nd quadrant at -10 on the y axis and up 6 on the x axis and then you go down 5 over 2

5 0
3 years ago
Read 2 more answers
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