Let after n week both tanks have same quantity of water .
for first tank
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tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
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quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
Answer: =−q+48.929073 <-- coming frm a calculator lol
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
If you need the y zero, you would take the 2 points on the graph of (3, 0) and (6, 0) so the 2 zero’s are 3, and 6.
<span>Let the number of nickles be x
Let the number of pennies be y
Value Value
Type Number of of
of of EACH ALL
coin coins coin coins
-------------------------------------------
nickles x $0.05 $0.05x
pennies y $0.01 $0.01y
-------------------------------------------
TOTALS 56 ----- $1.52
The first equation comes from the second column.</span>
