So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line


once you get the slope and solve for "y", that'd be the equation of the line.
Since this problem talks about rates of change, then the concept of calculus is very useful. But first, let's find at least two equations in order to solve this system. The first one is the area of a triangle written as
A = 1/2 ab sin θ, where a and b are the sides that from the angle θ. So, we substitute a=6 and b=10. That makes it:
A = 1/2 (6)(10)sin θ = 30 sin θ
Now, you differentiate implicitly (both sides simultaneously) with respect to time.
dA/dt = 30 cosθ (dθ/dt)
We replace dθ/dt = 0.06 rad/s, as mentioned in the problem. Then, the rate of change of the area of the triangle when θ = π/3 rad with respect to time is
dA/dt = 30cos(π/3) (0.06)
dA/dt = 1.8 m²/s
Therefore, the rate of change of the area of the triangle is 1.8 m² per second.
260,000-18,200 = 241,800 i think not posstive
Answer: ((x-y)*2)/5xy
Step-by-step explanation:
Similar rectangles have or form similar ratios. Hence to solve this, you have to get the ratio of the measurements:
Let N be the length of the similar rectangle
5/7 = 15/N
5(N) = 7(15) -> cross multiply
5N = 105
5N/5 = 105/5 -> divide both sides of the equation by 5
N = 21
Therefore, 21 meters in the length of the similar rectangle
To check -
5/7 = 15/21 (cross multiply)
105 = 105