Answer:
Can you please rewrite this correctly so I can solve?
Step-by-step explanation:
a)
total no. of pupils is not more than 24
therefore first equation is
(x+y) ≤ 24. ....(1)
No. of girls exceeding the no. of boys by atleast 4
(y-x) ≥ 4. .....(2)
b) Now Liza chooses 8 boys
Maximum no. of girls = ?
Using first inequality
y+8= 24 ( maximum value of less than or equal to function is equal to itself)
Therefore,
y= 24-8
=16
Minimum no. of girls = ?
Using second inequality
y-8 =4 (minimum value of greater than or equal to function is equal to itself)
Therefore,
y= 4+8
y=12
Answer:
a) 2linear inequalities
(x+y) ≤ 24
(y-x) ≥ 4
b) Max no. of girls = 16
Min no. of girls = 12
Hope it helps...
Answer:
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In a parallelogram opposites sides are parallel and congruent
so
In this problem
---> by opposite sides
substitute the given values
solve for x
Find the length of SV
substitute the value of x
Both a rhombus and a rectangle have diagonals that are perpendicular bisectors, but the ones formed in a square are all congruent, so that is probably the most descriptive one.
