3 years ago

How do you construct a line segment perpendicular to the segment given through the point given?

1 answer:

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Use the opposite reciprocal of the slope of the known line segment, then plug the point given as well as the opposite reciprocal of the slope into y = mx + b

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Step-by-step explanation:

all those numbers added equals 37.21

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By definition, the area of a rectangle is:

$A = w * l$

Where,

w: width of the rectangle

l: length of the rectangle

The total area is given by:

$A = A1 + A2$

Where,

A1: rectangular wooden board 1

A2: rectangular wooden board 2

Substituting we have:

$60 \frac{3}{8} = (6) (w) + (5\frac{1}{2}) (w)$

Rewriting we have:

$\frac{483}{8} = (6) (w) + (\frac{11}{2}) (w)$

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Answer:

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$w = 5 \frac{1}{4}$

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