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2 years ago

11

Find the two numbers that have a product of -15 and a sum of -2 A -5 B 5 C -3 D 3

1 answer:

Sergio [31]2 years ago

4 0

-5,3 are the numbers

-5+3=-15

while

-5+3 will also add up to -2

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The main cables of a suspension bridge are ideally parabolic. the cables over a bridge that is 400 feet logn are attached to tow

Novay_Z [31]

Consider the diagram of the problem.

Let the vertex be on the y axis, exactly, at the point (0, 40)

Another point of this parabola is (200, 100), as can be checked from the figure.

The vertex form of the equation of a parabola is :

$y=a(x-h)^{2}+k$ , where (h, k) is the vertex of the parabola,

replacing (h, k) with (0, 40), we have:

$y=ax^{2}+40$

to find a, we substitute (x, y) with (200, 100):

$100=a200^{2}+40$

40,000a=60

a=60/40,000=3/(2,000)

So, the equation of the parabola is $y= \frac{3}{2000} x^{2}+40$

4 0

3 years ago

You work at a T-shirt printing business. Of the 2,800 T-shirts shipped, 396 have a defect. What is the experimental probability

ElenaW [278]

396 out of 2800 shirts are defected.
396/2800 * 100 = 14.1% of the shirts were defected

7 0

3 years ago

Read 2 more answers

The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.

Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

$h(t)=-16t^2+80t+64$

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A) Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

so

For h(t)=0

$-16t^2+80t+64=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+80t+64=0$

so

$a=-16\\b=80\\c=64$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{10,496}} {-32}$

$t=\frac{-80+\sqrt{10,496}} {-32}=-0.70$

$t=\frac{-80-\sqrt{10,496}} {-32}=5.70$

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

$-16t^2+80t+64=40$

$-16t^2+80t+24=0$

Solve the quadratic equation

we have

$a=-16\\b=80\\c=24$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{7,936}} {-32}$

$t=\frac{-80+\sqrt{7,936}} {-32}=-0.28$

$t=\frac{-80-\sqrt{7,936}} {-32}=5.28$

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

3 0

2 years ago

Halfway between 2270and2370

saveliy_v [14]

700 is what is half of that I think

4 0

2 years ago

Read 2 more answers

What is the coefficient of q<br> (2/3q-3/4) and -1/6q-r)

kirza4 [7]

The coefficient in (2/3q-3/4) is 2/3 and in (-1/6q-r) is -1/6

4 0

3 years ago