Answer:
There are 118 plants that weight between 13 and 16 pounds
Step-by-step explanation:
For any normal random variable X with mean μ and standard deviation σ : X ~ Normal(μ, σ)
This can be translated into standard normal units by :
Let X be the weight of the plant
X ~ Normal( 15 , 1.75 )
To find : P( 13 < X < 16 )
![= P(\frac{( 13 - 15 )}{1.75} < Z < \frac{( 16 - 15 )}{1.75})](https://tex.z-dn.net/?f=%3D%20P%28%5Cfrac%7B%28%2013%20-%2015%20%29%7D%7B1.75%7D%20%3C%20Z%20%3C%20%5Cfrac%7B%28%2016%20-%2015%20%29%7D%7B1.75%7D%29)
= P( -1.142857 < Z < 0.5714286 )
= P( Z < 0.5714286 ) - P( Z < -1.142857 )
= 0.7161454 - 0.1265490
= 0.5895965
So, the probability that any one of the plants weights between 13 and 16 pounds is 0.5895965
Hence, The expected number of plants out of 200 that will weight between 13 and 16 = 0.5895965 × 200
= 117.9193
Therefore, There are 118 plants that weight between 13 and 16 pounds.
Cos A) 16/20 or 4/5
Tan A) 12/16 or 3/4
Sin A) 12/20 or 3/5
If the shirts all cost the same you would do 120 divided by 10 and that’s 12.you then multiple 31 by 12 and you get 372 so d
Answer:
15
Step-by-step explanation:
195/13=15
Answer:
F. 65°
Step-by-step explanation:
arc GD = 360 - (105+125)
arc GD = 360 - 230
arc GD = 130
<DEG = 1/2 (arc GD)
<DEG = 1/2 (130)
<DEG = 65°