Tina sells homemade crafts online. Her online

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

4 years ago

If f(x) varies directly with x and f(x)=40 when x=8, find the value of f(x) when x=2.

melamori03 [73]

f(x)=40

x=8

so if x=2 it would be 40/8 which is 5

6 0

3 years ago

Read 2 more answers

M^2-10m+9=(m-9)( ) filling the missing factor to complete the equation

Romashka [77]

Answer:

m-1

Step-by-step explanation:

3 0

3 years ago

A salesperson earns $450.20 per week plus 15% of her weekly sales. Which of the following describes the sales necessary for the

lapo4ka [179]

First we must construct an equation to model the problem. (In this case we will use an inequality instead) This is what I came up with:
450.20+0.15s>=600.10

This equation shows how if her base earnings ($450.20) are added to 15% of her sales, represented by s, then the total will be greater than or equal to $600.10
Next, we simply solve for s. (steps shown below)

1) 450.20+0.15s>=600.10 (simply restating the inequality)
2) 0.15s>=149.90 (here I isolated the variable)
3)0.15s/0.15>=149.90/0.15 (Finally I solve for s by dividing both sides by 0.15, this will isolate s on the left and leave the answer on the right)
4) s>=999.33... (here I found the total sales the salesperson would need to reach his/her goal of earning a minimum of $600.10; the 3's after the decimal are repeating so in the next step I will round up to the nearest hundredth (b/c this is what money is rounded to and if I round down he/she would make less than her goal. This means i must round up.))
5) s>=999.34 (simple rounding; once again I rounded up b/c rounding down would slightly bring the total earnings to less than the goal)

Therefore, the salesperson would need his/her sales to be $999.34 in order for his/her total earnings for the week to be at least $600.10 (greater than or equal to $600.10)

Hope this helped!

4 0

4 years ago

Find X (Show Your Work) WILL MARK BRAINLIEST!

Rudiy27

Answer:

its 8 cause 2 times x is 40 40+-40= 0 so 2 times 4 is 8

Step-by-step explanation:

6 0

3 years ago