Given: m∠A = m∠C = 90° AB ║ DC Prove: ∆ABD ≅ ∆CDB 40 points
1 answer:
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The closest distance between point A and point A' is 8.5 ⇒ B
Step-by-step explanation:
Let us revise the translation of a point
- If the point (x , y) translated horizontally to the right by h units then its image is (x + h , y)
- If the point (x , y) translated horizontally to the left by h units then its image is (x - h , y)
- If the point (x , y) translated vertically up by k units then its image is (x , y + k)
- If the point (x , y) translated vertically down by k units then its image is (x , y - k)
∵ Point A is located at (-5 , 2)
∵ Point A is translated 8 units to the right and 3 units up
- That means add x-coordinate by 8 and add y-coordinate by 3
∴ Point A' located at (-5 + 8 , 2 + 3)
∴ Point A' located at (3 , 5)
The distance between two points and
is
∵ Point a = (-5 , 2) and point A' = (3 , 5)
∴ = -5 and
= 3
∴ = 2 and
= 5
- Substitute these values in the rule of the distance
∵
∴
∴
∴
∴ d = 8.544 ≅ 8.5
The closest distance between point A and point A' is 8.5
Learn more:
You can learn more about the distance between two points in brainly.com/question/6564657
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