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Blizzard [7]
3 years ago
15

Kai is making a chessboard using pieces of wood that measure 1sq in when she finishes the chessboard well have an area of 64 sq

in how many pieces of wood should he put along each side
Mathematics
1 answer:
Kay [80]3 years ago
3 0

Answer:

8 pieces of wood should be put along each side of the chessboard

Step-by-step explanation:

Here in this question, we are interested in knowing the the number of pieces of wood that should be put along each side of the cheese board.

Firstly, to know the number of pieces of wood to use, we need to divide the area of the board by the area of each piece of wood

Mathematically that would be 64 square inches/ 1 square inch = 64 pieces of wood

64 pieces of wood would be needed to complete the cheeseboard.

The number of pieces to put along each side of the cheese board will be √64.

This is because the shape of a chessboard is square.

Thus the number of pieces to put on each side will be √64 = 8

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(2^3)^7 (2^-9)^2 how do i put that in exponential form​
jok3333 [9.3K]

Answer:

2³ = 8

Step-by-step explanation:

According to the laws of exponents, when raising a power to another power, you need to multiply the exponents.  After you multiply each set of exponents by the additional power, then it become a multiplication problem where the base is the same.  When multiplying exponents with the same base, you keep the base and add the exponents:  

(2^{3})^{7}*(2^{-9})^{2}=2^{21}*2^{-18}=2^{21+-18}=2^{3}

7 0
3 years ago
What measurement is equal to 24 kilograms
Vladimir79 [104]
52.9109 in pounds if that's what your asking.
3 0
4 years ago
Read 2 more answers
What is the answer ti<br> Y-7-x<br> 2x-y=8
TEA [102]
<span>2x+y=8
2x+x-7=8
3x=15

x=5 

y=5-7
y=-2</span>
3 0
4 years ago
NEED HELP ASAP PLEASE
Ilya [14]

Answer:

see explanation

Step-by-step explanation:

Given

A = \frac{1}{2} bh

a. substitute b = 6 and h = 5 into the formula

A = \frac{1}{2} × 6 × 5 = \frac{1}{2} × 30 = 15 units²

b.

Multiply both sides of the formula by 2

2A = bh, that is

bh = 2A ← divide both sides by b

h = \frac{2A}{b} = \frac{2(16)}{4} = \frac{32}{4} = 8

c

Using

bh = 2A ← divide both sides by h

b = \frac{2A}{h} = \frac{2(12)}{4} = \frac{24}{4} = 6

3 0
3 years ago
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
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