Answer:
y= 34/23
x= 123/46
Step-by-step explanation:
Solve for x
8x-5y= 14
x= 14/8 +5/8y
Sub x into second equation
– 5х+бу = -3
-5(14/8 +5/8y) + 6y= -3
-29/4 +23/8y = -3
y= 34/23
Sub y into any equation and solve for x
8x=483/23
x= 123/46
Answer: Second option.
Step-by-step explanation:
You need to use the following formula:
Where "B" is the area of its base and "h" is the height.
According to the data given in the exercise, you know that:
Therefore, knowing this values, you can substitute them into the formula shown before and then evaluate, in order to calculate the volume of thi right pyramid whose base is a regular hexagon.
Then, you get:
Answer:
30.25 in decimal form
30 1/4 in fraction form
Step-by-step explanation:
12(3) − 3(1/3) / 4(3)− (5) = 30.25 or 30 1/4
h = 9.2 cm
Solution:
Base of smaller triangle = 5 cm
Height of smaller triangle = 2.3 cm
Base of larger triangle = 15 cm + 5 cm = 20 cm
Height of larger triangle = h
Multiply by 20 on both sides.
9.2 = h
So that Ryan should have add 15 and 5 to get a denominator of 20 on the right sides of the first line. Doing so gives the correct value, h = 9.2 cm.
Answer:
- m = 4/3; b = -4
- m = 3; b = -6
Step-by-step explanation:
In each case, <em>solve for y</em>. You do this by getting the y-term by itself, then dividing by the coefficient of y.
<h3>1.</h3>
-3y = -4x +12 . . . . . subtract 4x
y = 4/3x -4 . . . . . . . divide by -3
The slope is 4/3; the y-intercept is -4.
__
<h3>2.</h3>
y = 3x -6 . . . . . . divide by 2
The slope is 3; the y-intercept is -6.
_____
<em>Additional comment</em>
Whatever you do to one side of the equation, you must also do to the other side. When we say "subtract 4x", that means 4x is subtracted from both sides of the equation. The reason for doing that in the first equation is to eliminate the 4x term from the left side.
(Sometimes, you may see operations described as "move ...". There is no property of equality called "move." There are <em>addition</em>, <em>subtraction</em>, <em>multiplication</em>, <em>division</em>, and <em>substitution</em> properties of equality. Any equation solving process will make use of one or more of these.)
