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Lera25 [3.4K]
4 years ago
13

a card is chosen at random from a deck of 52 cards. it is replaced and a second card is chosen. what is the probability of choos

ing a king and an ace?
Mathematics
2 answers:
serious [3.7K]4 years ago
7 0
P(2 aces) = (1/13)^2 
P(2 kings) = (1/13)^2 

P(king and ace) = 8C2/52C2 - 2(1/13)^2 = 0.0152 
Ksju [112]4 years ago
7 0

Answer:

\frac{1}{169}

Step-by-step explanation:

Total cards = 52

Total ace = 4

So probability of getting ace on first draw = \frac{4}{52}

Now the card is replaced .

So, Total cards = 52

Total kings = 4

So probability of getting kings on second draw = \frac{4}{52}

So,  the probability of choosing a king and an ace:

=  \frac{4}{52} \times \frac{4}{52}

=  \frac{1}{169}

Hence the probability of choosing a king and an ace is  \frac{1}{169}

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To solve this problem, we use the formula:

z = (x – u) / s

where z is the z score value which can be obtained from the tables, x is the sample value, u is the mean = 6.3 min, and s is the std dev = 2.2 min

 

at P value = 0.90, the z = 1.28, finding for x:

x = z s + u

x = 1.28 * 2.2 + 6.3

x = 9.116

 

at P value = 1.0, the z = 3.49, finding for x:

x = z s + u

x = 3.49 * 2.2 + 6.3

x = 13.978 ~ 14

 

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EXPLANATION:

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Multiply both nominators and denominators
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Read 2 more answers
BRAINLIEST FOR AN ACTUAL ANSWER
Andreyy89

Answer:

The correct pair of functions is the third one:  h(x)=(x−24)^2 and g(x)=x2

Step-by-step explanation:

Example:  If we have q(x) = x^2 and its graph, moving the vertex of this graph 24 units to the right results in r(x) = (x - 24)^2.

The correct pair of functions is the third one:  h(x)=(x−24)^2 and g(x)=x2

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