Question

a card is chosen at random from a deck of 52 cards. it is replaced and a second card is chosen. what is the probability of choosing a king and an ace?

Answer 1

P(2 aces) = (1/13)^2 
P(2 kings) = (1/13)^2 

P(king and ace) = 8C2/52C2 - 2(1/13)^2 = 0.0152 

Answer 2

Answer:

$\frac{1}{169}$

Step-by-step explanation:

Total cards = 52

Total ace = 4

So probability of getting ace on first draw = $\frac{4}{52}$

Now the card is replaced .

So, Total cards = 52

Total kings = 4

So probability of getting kings on second draw = $\frac{4}{52}$

So,  the probability of choosing a king and an ace:

=  $\frac{4}{52} \times \frac{4}{52}$

=  $\frac{1}{169}$

Hence the probability of choosing a king and an ace is  $\frac{1}{169}$