To solve this problem, we use the formula:
z = (x – u) / s
where z is the z score value which can be obtained from
the tables, x is the sample value, u is the mean = 6.3 min, and s is the std
dev = 2.2 min
at P value = 0.90, the z = 1.28, finding for x:
x = z s + u
x = 1.28 * 2.2 + 6.3
x = 9.116
at P value = 1.0, the z = 3.49, finding for x:
x = z s + u
x = 3.49 * 2.2 + 6.3
x = 13.978 ~ 14
Therefore the longest 10% calls last about 9.1 minutes to
14 minutes
9001
Or any whole number less than 9500
ANSWER:
The answer would be C. 54/7
EXPLANATION:
Multiply 9* 6/7 = 9x6/1x7 = 54/7
Multiply both nominators and denominators
Result to keeping the lowest possible denominator GCD(54, 7).
GCD - 54 / 1 = 53
7 / 1 = 7
Answer:
The answer is 12ac^14/b^3
Answer:
The correct pair of functions is the third one: h(x)=(x−24)^2 and g(x)=x2
Step-by-step explanation:
Example: If we have q(x) = x^2 and its graph, moving the vertex of this graph 24 units to the right results in r(x) = (x - 24)^2.
The correct pair of functions is the third one: h(x)=(x−24)^2 and g(x)=x2
Note: the fourth pair is incorrect, because the " + " sign moves the graph of x^2 24 units to the left.