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Dimas [21]
4 years ago
14

Bryan has a square parcel of land that is 120 yards long and 120 yards wide. The land is planted with Bermuda grass and surround

ed by a fence. So that his cattle will not ruin the grass, Bryan decides to split the field into two halves and rotate his cattle on the land every 30 days. He plans to build a fence diagonally across the field. How many feet of fencing will Bryan need to split the parcel of land in half? Round your answer to the nearest yard.
Mathematics
2 answers:
Law Incorporation [45]4 years ago
8 0

Answer:

170

Step-by-step explanation:

It's 170 for plato students.

Mekhanik [1.2K]4 years ago
6 0
The diagonal fencing will be the hypotenuse of a right triangle with sides 120yds long so:

h=√2(120^2))

h=√28800 yd

And the surrounding fencing will just be four times the side length of 120yds so:

s=480yd

So the total fencing needed is:

f=480+√28800 yards

f≈649.71 yd  (to nearest hundredth of a yard)  which is

f≈650 yds  (to nearest whole yard)

But, I wasn't sure, if they just want the diagonal fencing needed then it is just:

f=√28800

f≈170 yds  (to nearest yard)


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Which of the following describes the transformation from Figure 1 to Figure 2?​
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6 0
3 years ago
At a farm, the average number of chickens, ducks, rabbits and sheep is 315 per type of animal. The average number of chickens, d
Greeley [361]

The average number of chickens, ducks, rabbits and sheep = 315 per type of animal.

The average number of chickens, ducks and rabbits = 320 per type of animal.

The number of sheep is 60 more than the number of rabbits.

Let us assume number of rabbits = x.

Number of sheep is 60 more than number of rabbits, that is = x+60.

There are half as many ducks as there are rabbits.

Therefore, number of ducks = x/2.

Let us assume number of chickens = y.

Adding  number of chickens, number of rabbits, number of sheep and number of ducks and dividing by 4 (because those are four types of animal).

\frac{y+x+x+60+x/2}{4}  = 315

Multiplying both sides by 4, we get

y+x+x+60+x/2 = 1260

Subtracting 60 from both sides

y+x+x+60-60+x/2 = 1260-60

y+x+x+x/2 = 1200.

Combining like terms .

y + 5x/2 = 1200

Multiplying both sides by 2, we get

<em>2y +5x = 2400  ------------equation (1)</em>

Adding  number of chickens, number of rabbits and number of ducks and dividing by 3 (because those are three types of animal).

\frac{y+x+60+x/2}{3}  = 320

Multiplying both sides by 3, we get

y+x+60+x/2 = 960

Subtracting 60 from both sides

y+ x+x/2 = 900

Combining like terms .

y+ 3x/2 = 900

Multiplying both sides by 2, we get

<em>2y+3x = 1800 --------------------equation (2)</em>

Multiplying first equation by 3 and second equation by -5, we get

(2y +5x = 2400 ) * 3   => 6y +15x = 7200

(2y+3x = 1800) *-5      =>

Adding

6y +15x = 7200

-10x + -15x = -9000.

_________________

-4y = -1800.

Dividing both sides by -4, we get

y=450.

<h3>Therefore, number of chickens are  450 there at the farm.</h3>


7 0
3 years ago
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