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2 years ago

At Ralph's fruitstand three apples cost of $.90 you want to buy seven apples how much will they cost

Mathematics

1 answer:

Nata [24]2 years ago

3 0

1 apple is $.30. $.30 times 7 = $2.10.

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3/5 with an exponent of 4

nordsb [41]

Step-by-step explanation:

$\text{If is}\ \dfrac{3}{5}^4,\ \text{then}\ \dfrac{3}{5}^4=\dfrac{3\cdot3\cdot3\cdot3}{5}=\dfrac{81}{5}=16\dfrac{1}{5}\\\\\text{If is}\ \left(\dfrac{3}{5}\right)^4=\left(\dfrac{3}{5}\right)\left(\dfrac{3}{5}\right)\left(\dfrac{3}{5}\right)\left(\dfrac{3}{5}\right)=\dfrac{3\cdot3\cdot3\cdot3}{5\cdot5\cdot5\cdot5}=\dfrac{81}{625}$

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3 years ago

Divide 254 by 11.8. Round your answer to the nearest hundredth. A. 20.97 B. 21.53 C. 21.35 D. 22.07

Rainbow [258]

The answer is B 21.53

7 0

3 years ago

Read 2 more answers

Some help please? Which polynomial represents the difference below?

Helga [31]

So the right answer is of option D.

Look at the attached picture⤴

Hope it will help u...

4 0

2 years ago

Read 2 more answers

The researcher has limited resources. He sends 9 emails from a Latino name, and 14 emails from a non-Latino name. For the Latino

deff fn [24]

Answer: 38.41 minutes

Step-by-step explanation:

The standard error for the difference in means is given by :-

$SE.=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2}}$

where , $\sigma_1$ = Standard deviation for sample 1.

$n_1$ = Size of sample 1.

$\sigma_2$ = Standard deviation for sample 2.

$n_2$ = Size of sample 2.

Let the sample of Latino name is first and non -Latino is second.

As per given , we have

$\sigma_1=82$

$n_1=9$

$\sigma_2=101$

$n_2=14$

The standard error for the difference in means will be :

$SE.=\sqrt{\dfrac{(82)^2}{9}+\dfrac{(101)^2}{14}}$

$SE.=\sqrt{\dfrac{6724}{9}+\dfrac{10201}{14}}$

$SE.=\sqrt{747.111111111+728.642857143}$

$SE.=\sqrt{1475.75396825}=38.4155433158\approx38.41$

Hence, the standard error for the difference in means =38.41 minutes

3 0

2 years ago

What is the difference of polynomials (8r6s3-9r5s4+3r4s5)-(2r4s-5r6-4r5s4)

Alinara [238K]

If you would like to solve (8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4), you can do this using the following steps:

(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4) = 8r^6s^3 – 9r^5s^4 + 3r^4s^5 – 2r^4s^5 + 5r^3s^6 + 4r^5s^4 = 8r^6s^3 – 5r^5s^4 + r^4s^5 + 5r^3s^6

The correct result would be 8r^6s^3 – 5r^5s^4 + r^4s^5 + 5r^3s^6.

7 0

3 years ago