<span>1. Solve the system by substitution -2x+y=-11, 3x-4y=11.
</span>-2x+y=-11<span>
y = 2x-11
</span><span>3x-4y=11
</span>3x-4(2x-11)=11
3x -8x + 44 = 11
-5x = -33
<span>x =33/5
y = 11/5
</span><span>2. Solve the system using elimination- 2x+6y=-12, 5x-5y=10.
</span><span>(-2x+6y=-12)5
</span>-10x + 30y = -60
<span>(5x-5y=10)2
</span>10x - 10y = 20
Adding the two equations,
<span>-10x + 30y = -60
</span><span>10x - 10y = 20
</span>
20y = -40
y = -2
x = 0
<span>3. What is the solution of the following system?-3x-2y=-12, 9x+6y=-9.
</span><span>-3x-2y=-12
</span>y = -3/2 x + 6
<span>9x+6y=-9
</span>y = -3/2 x - 3/2
Since the slopes are equal then they are parallel lines so they never meet at one point.
sorry i don't know the answer to this question
Answer:
The two page numbers are 78 and 79.
Step-by-step explanation:
Let's take the page numbers are x and x + 1
.
The produce of the page numbers is 6162
so, x(x + 1) = 6162
Here we have to use the quadratic formula to solve for x.
The quadratic formula, x = 
Here a =1, b = 1 and c = -6162
Plugging in the value of a, b and c in the above formula, we get
x = [-1 ± 157] ÷ 2
Let's take the positive value alone since the page number cannot be negative.
x = [-1 + 157]
÷2
x = 78
The next page number x + 1 = 78 + 1 = 79
Therefore, the two page numbers are 78 and 79.
The answer to this question is zero
9514 1404 393
Answer:
x = 14°
Step-by-step explanation:
The triangle's interior angle at C is the supplement of the exterior angle marked 124°.
C = 180° -124° = 56°
The exterior angle at B is the sum of the remote interior angles:
6x = 56° +2x
4x = 56° . . . . . . subtract 2x
x = 14° . . . . . . . . divide by 4
