Question

Which number can each term of the equation be multiplied by to eliminate the decimals before solving?

Answer 1

Ok...

5.6 = 56/10 = 560/100

1.1 = 11/10 = 110/100

0.12 = 12/100

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$\frac { 560 }{ 100 } j-\frac { 12 }{ 100 } =4+\frac { 110 }{ 100 } j\\ \\ \\ 100\times \left( \frac { 560 }{ 100 } j-\frac { 12 }{ 100 } \right) =\left( 4+\frac { 110 }{ 100 } j \right) \times 100\\ \\ 560j-12=400+110j\\ \\ 560j-110j=400+12\\ \\ 450j=412\\ \\ j=\frac { 412 }{ 450 }$

So, the answer is: 100

You could multiply both sides of the equation by 100 to get the value of (j) quickly.

Answer 2

Answer:

100.

Step-by-step explanation:

We have been given an equation $5.6j-0.12=4+1.1j$. We are asked to find the number, by which we can multiply our given equation to eliminate decimals.

We can see from our given equation that 0.12 has two digits after decimal, so we need to multiply our equation by 100 to eliminate as after multiplying by 100 the decimal will shift to right by 2 digits.

After multiplying our given equation by 100 we will get,

$100*(5.6j-0.12)=100(4+1.1j)$

$560j-12=400+110j$

Therefore, our required number is 100.