Answer:
2
Step-by-step explanation:
A = P( 1+r/n) ^ (nt)
P is the amount invested
r is the rate
n is the number of times per year the interest is compounded
t is the number of years
every 6 months is twice a year
so n is 2
<u>Answer:</u>
The grade you make on your exam varies directly with the number of correct answers. The constant of variation is 5
<u>Solution:</u>
Given, The grade you make on your exam varies directly with the number of correct answers you get on the exam.
Answering 15 questions correctly will give you a grade of 75 what is the.
We have to find what is the Constant of variation.
Now, according to the given information, grade number of correct answer
Then, grade = c x number of correct answers, where c is constant of variation.
Now, substitute grade = 75 and number of correct answers = 15
![\text { Then, } 75=c \times 15 \rightarrow c=\frac{75}{15}=5](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Then%2C%20%7D%2075%3Dc%20%5Ctimes%2015%20%5Crightarrow%20c%3D%5Cfrac%7B75%7D%7B15%7D%3D5)
Hence, the constant of variation is 5
Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.
<h3>Zeros of a function</h3>
The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.
In summary, the roots or zeros of the quadratic function are those values of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.
In a quadratic function that has the form:
f(x)= ax² + bx + c
the zeros or roots are calculated by:
![x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}](https://tex.z-dn.net/?f=x1%2Cx2%3D%5Cfrac%7B-b%2B-%5Csqrt%7Bb%5E%7B2%7D-4ac%20%7D%20%7D%7B2a%7D)
<h3>This case</h3>
The quadratic function is f(x) = x² + 4x +9
Being:
the zeros or roots are calculated as:
![x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}](https://tex.z-dn.net/?f=x1%3D%5Cfrac%7B-4%2B%5Csqrt%7B4%5E%7B2%7D-4x1x9%20%7D%20%7D%7B2x1%7D)
![x1=\frac{-4+\sqrt{16-36 } }{2x1}](https://tex.z-dn.net/?f=x1%3D%5Cfrac%7B-4%2B%5Csqrt%7B16-36%20%7D%20%7D%7B2x1%7D)
![x1=\frac{-4+\sqrt{-20 } }{2x1}](https://tex.z-dn.net/?f=x1%3D%5Cfrac%7B-4%2B%5Csqrt%7B-20%20%7D%20%7D%7B2x1%7D)
and
![x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}](https://tex.z-dn.net/?f=x2%3D%5Cfrac%7B-4-%5Csqrt%7B4%5E%7B2%7D-4x1x9%20%7D%20%7D%7B2x1%7D)
![x2=\frac{-4-\sqrt{16-36 } }{2x1}](https://tex.z-dn.net/?f=x2%3D%5Cfrac%7B-4-%5Csqrt%7B16-36%20%7D%20%7D%7B2x1%7D)
![x2=\frac{-4-\sqrt{-20} }{2x1}](https://tex.z-dn.net/?f=x2%3D%5Cfrac%7B-4-%5Csqrt%7B-20%7D%20%7D%7B2x1%7D)
If the content of the root is negative, the root will have no solution within the set of real numbers. Then
has no solution.
Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.
Learn more about the zeros of a quadratic function:
brainly.com/question/842305
brainly.com/question/14477557
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Answer:
Answer: A
Step-by-step explanation: