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Stella [2.4K]
2 years ago
11

A lap around a track is 2/5 of a mile. how many laps is a 1 1/2 mile race?

Mathematics
2 answers:
taurus [48]2 years ago
8 0

Answer: 3 3/4

Step-by-step explanation:

1 1/2=3/2, so 3/2 divided by 2/5 is 15/4 which is 3 3/4

sergiy2304 [10]2 years ago
4 0

Answer:

3 3/4

Step-by-step explanation:

3/2/2/5 = 15/4

15/4 = 3 3/4

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Can someone double check my answers on this integers sheet? (53 points)
MatroZZZ [7]
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4 0
3 years ago
Please help me! 15 points
arsen [322]

Answer:

a. The length of FA is 1.

b. The length of the radius (AC) is 2.

c. The circumference of the circle A is 4π units.

d. The measure of the minor arc BC is 107°.

e. The length of the minor arc BC is (107/90) π.

f. The m<BFC and m<EFD is 125.5°.

g. The m<BFE is 180°.


Step-by-step explanation:

Radius: R=AB=2

FC=1

Arc CD = 180°

Minor arc BD = 73°

Minor arc EC = 36°


a. What is the length of FA?

FA=AC-FC

AC is a radius, then AC=AB→AC=2

Replacing in the known values in the equation above:

FA=2-1

FA=1


b. What is the length of the radius (AC)?

The radius AC must be equal to the radius AB, then:

AC=AB→AC=2


c. What is the circumference of the circle A?

Circunference of circle A: L=?

L=2 π R

L=2 π (2)

L=4π


d. What is the measure of the minor arc BC?

Minor arc BC = arc CD - Minor arc BD

Minor arc BC = 180°-73°

Minor arc BC = 107°


e. What is the length of the minor arc BC?

Length of minor arc BC: l=?

l=(Minor arc BC / 360°) L

l=(107°/360°) 4π

l=(4*107/360) π

l=(107/90) π


f.  What is the m<BFC and m<EFD

<BFC and <EFD are interior angles, then:

m<BFC = m<EFD = ( Minor arc BC + Minor arc DE) / 2

Minor arc DE = arc CD - Minor arc EC

Minor arc DE = 180°-36°

Minor arc DE = 144°

m<BFC = m<EFD = ( 107° + 144° ) / 2

m<BFC = m<EFD = ( 251° ) / 2

m<BFC = m<EFD = 125.5°


g. What is the m<BFE?

<BFE is a straight angle, then m<BFE=180°





8 0
3 years ago
It is urgent plz answer
Mamont248 [21]

Answer:

my class is 8 th is I don't now this answer

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