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Kipish [7]
3 years ago
12

Whats the pattern of -128 , 64, -32, 16

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0
-128, 64, -32, 16, -8, 4, -2, etc.
This is how the pattern should end.
All of these numbers are divided by -2. 
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When simplifying 4x^3-10x^2+6x/2x^3+x^2-3x, what are the term(s) that can be cancelled
brilliants [131]

Answer:

x can be cancelled

Step-by-step explanation:

we are given

\frac{4x^3-10x^2+6x}{2x^3+x^2-3x}

Firstly, we will factor numerator and denominator

and then we can factor it

4x^3-10x^2+6x=2x(2x^2-5x+3)

4x^3-10x^2+6x=2x(2x+1)(x-3)

now, we can factor denominator

2x^3+x^2-3x=x(2x^2+x-3)

2x^3+x^2-3x=x(x-1)(2x+3)

now, we can replace it

\frac{4x^3-10x^2+6x}{2x^3+x^2-3x}=\frac{2x(2x+1)(x-3)}{x(x-1)(2x+3)}

we can see that

both terms are having x common

so, x can be cancelled

So,

x can be cancelled

3 0
3 years ago
Which of the following congruency statements is correct?
xxMikexx [17]
I don’t think any of them are correct .. but I may be wrong
3 0
3 years ago
Read 2 more answers
Which expression represents a<br> positive integer?<br> F. – 6²<br> H. (-5)<br> G. (-3)<br> 1.-23
marta [7]
F -6*-6 = 36 which is a positive interger
3 0
3 years ago
People in here again and again. I think this is the last question
Lilit [14]

Answer:

2.4 cm

Step-by-step explanation:

We know the length of segment AB and the length of segment BC. To find their midpoints, we can divide their length by 2.

Let's find the midpoint of AB.

  • Segment AB: 10 cm
  • Midpoint of AB: 10/2 = 5 cm

Next let's find the midpoint of BC.

  • Segment BC: 5.2 cm
  • Midpoint of BC: 5.2/2 = 2.6 cm

In order to find the difference between these midpoints, we can subtract the midpoint of AB by the midpoint of BC.

  • 5 cm - 2.6 cm = 2.4 cm

Therefore, the difference between the midpoints of AB and BC is 2.4 cm.

5 0
3 years ago
A motorboat takes 5 hours to travel 200 miles going upstream. The return trip takes 4 hours going downstream. What is the rate o
dsp73

Answer:

rate of motorboat: b

rate of current: c

So the rate the boat travels upstream is $b - c$, and the rate it travels downstream is $b + c$

Step-by-step explanation:

d = rt

200 = (b - c)\cdot 5

200 = (b + c)\cdot 4

b - c = 40

b + c = 50

Adding these equations, we get:

2b = 90

b = 45

So

c = 50 - 45 = 5

<u>Therefore the rate of the boat is 45kph, and the rate of the current is 5kph</u>

Hope this helps :)

4 0
3 years ago
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