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Kipish [7]
3 years ago
12

Whats the pattern of -128 , 64, -32, 16

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0
-128, 64, -32, 16, -8, 4, -2, etc.
This is how the pattern should end.
All of these numbers are divided by -2. 
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Help! How would I solve this trig identity?
NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}

Then the identity can be rewritten as:

sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\

Now we can multiply both sides by cos⁴(x) to get:

\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)

Now we can use the identity:

sin²(x) + cos²(x) = 1

1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

#SPJ1

7 0
1 year ago
The radius of a cylinder is measured in meters what unit will the surface area be measured in
iren2701 [21]
<h3>Answer: A) Square meters</h3>

Explanation:

Imagine that a parent bought a basketball for their son or daughter. If they wrapped the ball with wrapping paper, then that wrapping paper can be unwrapped to form a flat sheet. So the area of the sheet corresponds directly to the surface area. If the sheet is say 1 meter by 1 meter, then the area is 1*1 = 1 square meter. We can abbreviate "square meters" into "meter^2" or "m^2".

5 0
3 years ago
Read 2 more answers
A 10ft by 20ft rectangular swimming pool is surrounded by a walkway of uniform width. If the total area of the walkway is 216ft^
Dmitry [639]

check the picture below.


so, we know the dimensions of the pool, is a 20x10, so its area is simply 200 ft², and we know the walkway is 216 ft², so the whole thing, including pool and walkway is really 200 + 216 ft².


now, as you see in the picture, the dimensions for the combined area is 20+2x and 10+2x, since the walkway is "x" long, therefore,


\bf \stackrel{length}{(20+2x)}\stackrel{width}{(10+2x)}=200+216\implies \stackrel{FOIL}{4x^2+60x+200}=200+216 \\\\\\ 4x^2+60x=216\implies \stackrel{dividing~by~4}{x^2+15x=54} \\\\\\ x^2+15x-54=0\implies (x+18)(x-3)=0\implies x= \begin{cases} -18\\ \boxed{3} \end{cases}


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5 0
3 years ago
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Help please I need help
Eddi Din [679]

Answer:

x = 5/13

Step-by-step explanation:

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7 0
3 years ago
IM GIVING BRAINLIEST!! suppose F is a 10-newton vector direction 60 degrees north of east and g is a 12-newton vector directed 4
Sonbull [250]

Answer: The magnificent of east and g is a round out of the fraction that is in direct to 32 degrees and the other direction of the resultant 10 = 12 + F

45 = 60 + F.

8 0
2 years ago
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