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IrinaK [193]
3 years ago
6

For f(x)=2x+1 and g(x)=xsquared-7 find (f-g)(x)

Mathematics
1 answer:
devlian [24]3 years ago
5 0

Answer:

<em>(f-g)(x) = - x² + 2 x + 8</em>

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given f(x) = 2 x +1

          g(x) = x² - 7

(f-g)(x) = f(x) - g(x)

          = (2 x + 1) - ( x² -7)

         = - x² + 2 x + 1 + 7

       =  - x² + 2 x + 8

<em>(f-g)(x) = - x² + 2 x + 8     </em>

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No its not a prime number its actually a square number.
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(5x)+ (9y)+90 what is x and y
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Answer:

Step-by-step explanation:

5x+9y+90

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What is the equation of this circle in standard form M(2,4) N(9,4) these are coordinates across the diameter of the circle?
igomit [66]
The standard form is

(x-xo)² + (y-yo)² = r²

Where xo,yo is the center of the circumference
and r is the radius.

We find the distance between the points to determine the <span>diameter

d=sqrt ((9-2)</span>² + (4-4)²<span>) = sqrt (49) = 7

The radius of the circumference is d/2 = 7/2 = 3.5

And we can see that those points are at the same coordinate y = 4 

The center is given then by , x = (9+2)/2 = 5.5
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The equation results

(x-5.5)</span>² + (y-4)² = (3.5)²<span>

</span>
3 0
3 years ago
Let x denote the courtship time for a randomly selected female–male pair of mating scorpion flies (time from the beginning of in
gavmur [86]

Complete Question:

a) Is it plausible that X is normally distributed?

b) For a random sample of 50 such pairs, what is the (approximate) probability that the sample mean courtship time is between 100 min and 125 min?

Answer:

a) It is plausible that X is normally distributed

b) probability that the sample mean courtship time is between 100 min and 125 min is 0.5269

Step-by-step explanation:

a)X denotes the courtship time for the scorpion flies which indicates that is a real - valued random variable, and since normal distribution is a continuous probability distribution for a real valued random variable, it is plausible that X is normally distributed.

b) Probability that the sample mean courtship time is between 100 min and 125 min

\mu = 120\\n = 50

P(x_{1}  < \bar{X} < x_{2} ) = P(z_{2}  < \frac{x_{2}- \mu }{SD} ) - P(z_{1}  < \frac{x_{2}- \mu }{SD})

SD = \sqrt{\frac{\sigma^{2} }{n} } \\SD = \sqrt{\frac{110^{2} }{50} } \\SD = 15.56

P(100 < \bar{X}

From the probability distribution table:

P(z_{2}  < 0.32 ) = 0.6255\\ P(z_{1}  < -1.29) = 0.0986

P(100 < \bar{X}

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