Answer:
34.98yd^3
Step-by-step explanation:
Volume of a sphere V=4/3πr3
Where V = 2240yd^3
π = 3.14
2240 = 4/3×3.14×r^3
2240 = 4.1866r^3
r^3 = 2240/4.1866
r^3 = 534.784
r = ( 534.784 )^1/3
r = 8.1169
Since each dimension is to be multiplied by 1/4
Hence, 1/4×8.1169
r = 2.029.
New volume will be
V = 4/3×3.14×2.029^3
V = 4/3×3.14×8.3558
V = 34.98yd^3.
Answer:
1 3/4
Step-by-step explanation:
You can set it up like the distrubtive property first
3/4(2+ 1/3) Next you use the distirbutive property instead of adding inside the parenthesis and you multiply the 3/4 by 2 and then the 3/4 by 1/3
Use 2 as 2/1 in fraction problems
3/4 * 2/1 Now multiply the numerators together and the denomenators together
3 * 2 = 6 4 * 1 =4
6/4
3/4 *1/3
3 * 1 =3
4 * 3 =12
3/12
Now we have to make them both like terms (same denominator) so we can add them, we will multiply the 6/4 by 3 (Both top and bottom)
6 * 3 = 18 4 *3 =12
18/12
Now we add the fractions
3/12 +18/12 = 21/12
Reduce that and you get
21/12 = 1 9/12 or 1 3/4
The answer to this question is 4/6 because of the ratio changes to a division sign
Answer:
Explanation has been given below
Step-by-step explanation:
a) inter arrival times are exponentially distributed with mean 1/n , where n = rate = 1/sec.
probability distribution function is F(t)=n*exp(-n*t).
reference to any kth packet and the (k-1)th packet
the answer is = integration of F(t).dt with limits 0 to 2 = 1 - exp(-2*n) = 1 - exp(-2)
b) t=5 , P(q) = exp(-5)*(5)^q/factorial(q)
probability of fourth call within t=5 seconds is =
that is P(4) P(5) ...... = 1 - ( P(0) P(1) P(2) P(3) ) ; put the values and get the answer.
c) number of calls/rate = 4/n = 4 seconds
Answer:
That would be 19.6875 in decimal form.
Step-by-step explanation:
