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Let's find the derivative of that hyperbola in order to find a slope formula to help us with this equation. We already have an x and y value. The derivative is found this way: 
so 
. The derivative supplies us with the slope formula we need to write the equation. Sub in the x value of 3 to find what the slope is: 
. So in our slope-intercept equation, x = 3, y = 1, and m = -1/3. Use these values to solve for b. 
so b = 2. The equation, then, for the line tangent to that hyperbola at that given point is 