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love history [14]
4 years ago
7

Answer the question given in the picture---

Mathematics
1 answer:
tigry1 [53]4 years ago
6 0
Angle ABG because ABG+ABE= 180
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Which graduate can expect the highest average lifetime earnings?
uranmaximum [27]

Answer:

a college graduate

Step-by-step explanation:

8 0
2 years ago
A common test of strength engaged in by high school students at Elmhurst HS is seeing how much weight they can lift from the flo
Alexus [3.1K]

Answer:

a) 30.85% probability that 1 randomly selected male student has the best lift less than 200 lbs.

b) 2.28% probability the sample mean will be over 245 lbs.

c) Because the underlying population(weight the students can lift) is normally distributed.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 225, \sigma = 50

(a) Find the probability that 1 randomly selected male student has the best lift less than 200 lbs.

This is the pvalue of Z when X = 200. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{200 - 225}{50}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085

30.85% probability that 1 randomly selected male student has the best lift less than 200 lbs.

(b) If a sample of 25 students is tested, find the probability the sample mean will be over 245 lbs.

Now n = 25, s = \frac{50}{\sqrt{25}} = 10

This probability is 1 subtracted by the pvalue of Z when X = 245. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{245 - 225}{10}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability the sample mean will be over 245 lbs.

(c) Why can the normal distribution be used in part b even though the sample size is < 30?

The sample size being at least 30 condition is only if the underlying population is not normally distributed. In this case, it is, so we use the normal distribution in part b.

8 0
3 years ago
What's In
Kitty [74]

Answer:

4/5

1/2

1/5

1/2

2/3

Step-by-step explanation:

simply try to find a number that is a factor of both numbers in the fraction and divide it to simplify the fraction

8 0
3 years ago
The diagonal of a square is 15 inches. find the area of the square
kondor19780726 [428]
Think of the square as a rhombus:
\frac{15 \times 15}{2}  =  \frac{225}{2}  = 225 \div 2 = 112.5
so 112.5 square inches


you can ask if it wasn't clear enough, I will explain.
Have a nice day!!!!
3 0
4 years ago
Sakura speaks 150150150 words per minute on average in Hungarian, and 190190190 words per minute on average in Polish. She once
d1i1m1o1n [39]

Answer:

300 words in Hungarian and 570 in Polish.

Step-by-step explanation:

I guess you need to know the number of words in Hungarian and in Polish.

Let H be the words he said in Hungarian, and P the words he said in Polish.

We are told that Sakura uttered a total of 270 more words in Polish than in Hungarian, therefore:

P = H + 270

And that I speak for 5 minutes, we know that the speed of words in Hungarian is 150 and in Polish it is 190, therefore:

5 = H / 150 + P / 190

Thus we have two equations and two unknowns, that is, it has a solution, replacing P:

5 = H / 150 + (H +270) / 190

5 = (190 * H + 150 * H + 270 * 150) / (150 * 190)

5 * 150 * 190 = 340 * H + 270 * 150

H = (5 * 150 * 190 - 270 * 150) / 340

H = 300

Therefore he said 300 words in Hungarian.

In Polish it would be:

P = 300 + 270 = 570

To check we have to:

300/150 + 570/190 = 5

Therefore, Sakura giving the instructions said 300 words in Hungarian and 570 in Polish.

8 0
3 years ago
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