Answer the question given in the picture---

Pls help I’m failing I’ll brainlest

LenKa [72]

Answer:

6x

Step-by-step explanation:

Since 2 sides are equal to 3x-3, multiply 3x-3 by 2.

=6x-6

Subtract 18x+6 - 6x-6

= 12x

Since 2 there are 2 sides missing, 12x divided by 2

=6x

7 0

2 years ago

Select all that apply.

Mila [183]

First we need to have same units before comparing them. That is, either both of them are in cm or both of them are in mm. So if we need to convert 12.5 cm to mm, we know that 1 cm =10 mm. So we have to find out how many mm are in 12.5 cm. And let 12.5 cm =x mm. So to find the value of x , we set a proportion and solve for x. That is

$\frac{1cm}{10mm}=\frac{12.5cm}{x mm}$

The units cancel out and we do cross multiplication. That is

$1*x =12.5*10$

x=125

So 12.5 cm =125 mm. Therefore the correct proportion is C.

3 0

3 years ago

If a hiker starts at sea level and increases her elevation at a rate of 1 foot per minute what will her elevation be in 20 minut

sattari [20]

Answer:

20 feet above sea level.

Explanation:

This can be solved by looking at the Rate of Change. It is given that for ONE minute that passes by, her elevation increases by ONE foot.

With this rate, after 20 minutes, the elevation can be shown as:

20 min × 1 foot= 20 feet.

4 0

2 years ago

Read 2 more answers

Abby, Bernardo, Carl, and Debra play a game in which each of them starts with four coins. The game consists of four rounds. In e

Sedaia [141]

The probability that, at the tip of the fourth round, each of the players has four coins is 5/192.

Given that game consists of 4 rounds and every round, four balls are placed in an urn one green, one red, and two white.

It amounts to filling in an exceedingly 4×4 matrix. Columns C₁-C₄ are random draws each round; row of every player.

Also, let $\%R_{A}$ be the quantity of nonzero elements in $R_{A}.$

Let $C_{1}=\left(\begin{array}{l}1\\ -1\\ 0\\ 0\end{array}\right)$ .

Parity demands that $\%R_{A}$ and $\%R_{B}$ must equal 2 or 4.

Case 1: $\%R_{A}$ =4 and $\%R_B$ =4. There are $\left(\begin{array}{l}3\\ 2\end{array}\right)$ =3 ways to put 2-1's in $R_A$ , so there are 3 ways.

Case 2: $\%R_{A}$ =2 and $\%R_B$ =4. There are 3 ways to position the -1 in $R_A$ , 2 ways to put the remaining -1 in $R_B$ (just don't put it under the -1 on top of it!), and a pair of ways for one among the opposite two players to draw the green ball. (We know it's green because Bernardo drew the red one.) we are able to just double to hide the case of $\%R_{A}=4,\%R_{B}=2$ for a complete of 24 ways.

Case 3: $\%R_A=\%R_B=2$ . There are 3 ways to put the -1 in $R_{A}$ . Now, there are two cases on what happens next.

The 1 in $R_B$ goes directly under the -1 in $R_A$ . There's obviously 1 way for that to happen. Then, there are 2 ways to permute the 2 pairs of 1,-1 in $R_C$ and $R_D$ . (Either the 1 comes first in $R_C$ or the 1 comes first in $R_D$ .)
The 1 in $R_B$ doesn't go directly under the -1 in $R_A$ . There are 2 ways to put the 1, and a couple of ways to try and do the identical permutation as within the above case.

Hence, there are 3(2+2×2)=18 ways for this case. There's a grand total of 45 ways for this to happen, together with 12³ total cases. The probability we're soliciting for is thus 45/(12³)=5/192

Hence, at the top of the fourth round, each of the players has four coins probability is 5/192.

Learn more about probability and combination is brainly.com/question/3435109

#SPJ4

3 0

2 years ago

Read 2 more answers

In an equation what do v1 and v2 represent

Alik [6]

If this is regards to science and take off then <span>V1= Takeoff decision speed.
VR= Rotation speed. V2=Single engine climb speed. .</span>

6 0

3 years ago