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hoa [83]
2 years ago
10

Mrs. Peña is taking a group of 50 students on a field trip to the Georgia Aquarium. If 20 of the students are boys, what percent

of the students are boys?
Mathematics
1 answer:
sergiy2304 [10]2 years ago
5 0

Answer:

40%

Step-by-step explanation:

20/50 = 40/100 = 40%

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Harry's parrot is 11 years older than his cat.
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Answer:

The answer to your question is:   P = 17 years

Step-by-step explanation:

Data

Parrot = 11 years older than the cat

C = cat age

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8 0
3 years ago
What are the next 3 numbers in the number sequence?
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B

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31-23=8

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3 0
2 years ago
Read 2 more answers
The management of a department store is interested in estimating the difference between the mean credit purchases of customers u
Mkey [24]

Answer:

Step-by-step explanation:

1) Point estimate is the difference between the sample means. Therefore,

A point estimate for the difference between the mean purchases of the users of the two credit cards is = 140 - 125 = $15

2) Margin of error = z√(σ²/n1 + σ2²/n2)

Where

z is the z score from the 95% confidence level. From the normal distribution table, z = 1.96

s1 and s2 are standard deviation for both customers respectively.

Standard deviation = √variance

σ1 = √100 = 10

σ2 = √641 = 25.32

Margin of error = 1.96√(10²/64 + 25.32²/49 = 7.5

At 95% confidence, the margin of error is 7.5

3) The confidence interval for the difference of two population means is expressed as point estimate ± margin of error

Confidence interval = 15 ± 7.5

The upper boundary for the confidence interval is

15 - 7.5 = 7.5

The lower boundary for the confidence interval is

15 + 7.5 = 22.5

A 95% confidence interval estimate for the difference between the average purchases of the customers using the two different credit cards is $7.5 to $22.5

4) Since the population standard deviations are known, we would use the formula to determine the test statistic(z score)

z = (x1 - x2)/(√σ1²/n2 + σ2²/n2)

z = (140 - 125)/√10²/64 + 25.32²/49

z = 1.02

The test statistic for an alpha of .05 is 1.02

4 0
2 years ago
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