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vampirchik [111]
3 years ago
12

Can you find the marginal profit of a,b and c?

Mathematics
1 answer:
MakcuM [25]3 years ago
3 0
Keeping in mind that for a cost C(x) and profit P(x) and revenue R(x), the marginal cost, marginal profit and marginal revenue are respectively dC/dx, dP/dx and dR/dx, then

\bf P(x)=0.03x^2-3x+3x^{0.8}-4400
\\\\\\
\stackrel{marginal~profit}{\cfrac{dP}{dx}}=0.06x-3+2.4x^{-0.2}
\\\\\\
\cfrac{dP}{dx}=0.06x-3+2.4\cdot \cfrac{1}{x^{0.2}}\implies \cfrac{dP}{dx}=0.06x-3+2.4\cdot \cfrac{1}{x^{\frac{1}{5}}}
\\\\\\
\cfrac{dP}{dx}=0.06x-3+\cfrac{2.4}{\sqrt[5]{x}}

\bf a)\qquad 
\cfrac{dP}{dx}=0.06(200)-3+ \cfrac{2.4}{\sqrt[5]{200}}
\\\\\\
b)\qquad \cfrac{dP}{dx}=0.06(2000)-3+\cfrac{2.4}{\sqrt[5]{2000}}
\\\\\\
c)\qquad \cfrac{dP}{dx}=0.06(5000)-3+\cfrac{2.4}{\sqrt[5]{5000}}
\\\\\\
d)\qquad \cfrac{dP}{dx}=0.06(10000)-3+\cfrac{2.4}{\sqrt[5]{10000}}
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Answer:

i. No, Maurice statement is wrong.

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Step-by-step explanation:

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Since the piece of wood has a shape of a rectangle,

the area of the piece of wood = length × width

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According to Maurice's statement, he could make a tray that has a base of 1012 inches by 1012 inches.

The base has the shape of a square, so that;

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This shows that Stephan does not have sufficient wood to make the tray because the square inches required is more than what he has.

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