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Sliva [168]
3 years ago
10

Find the value of k if it is known that the graph of y=kx+2 goes through the point. a(14,-40)

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
8 0

Answer:

k=-3

Explanation:

Plug in x and y values

-40=k(14)+2

-2 both sidea

-42=k(14)

divide by 14 both sides

k=-3

zimovet [89]3 years ago
8 0

k = -3

Step-by-step explanation:

y = kx + 2 through the point a(14, -40)

Subtitute…

y = kx + 2

-40 = k(14) + 2

-40 = 14k + 2

-40 - 2 = 14k

-42 = 14k

(-42)/14 = k

<u>-3 = k</u>

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-1, 2, 6

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⇒\frac{(x-2)+x(x-6)}{(x-2)(x-6)} = \frac{4}{x^{2}-8x+12 }

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If, (x-2)(x-6) =0, then x=2 or x=6

If, [\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0, then x^{2} -5x-2=4

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So the solutions for x are -1, 2 6. (Answer)

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3 years ago
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Ede4ka [16]

Answer:

D.10÷3

Step-by-step explanation:

ir you try dividing the number 10 by 3 you would get 3.333333 non-stop.

8 0
3 years ago
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