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3 years ago

Look at the sequence : 5, -10, 20, -40, 80

Mathematics

2 answers:

Sphinxa [80]3 years ago

7 0

Answer:

5 (5x1) , -10 -(5x2), 20(10x2), -40 -(20x2), 80(40x2)

so the next number should be previous number in the sequence multiplied by 2 and a negative sign.

-`(80x2) = -160

bogdanovich [222]3 years ago

7 0

Answer:

5 (5x1) , -10 -(5x2), 20(10x2), -40 -(20x2), 80(40x2)

so the next number should be previous number in the sequence multiplied by 2 and a negative sign.

-`(80x2) = -160

Step-by-step explanation:

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2 years ago

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2 years ago

What are the solutions to the quadratic equation below x^2+20x+100=7

aleksandrvk [35]

First you must have the quadratic equal to zero. In order to do this you must subtract 7 to both sides

x^2 + 20x + (100 - 7) = 7 - 7

x^2 + 20x + 93 = 0

Now you must find two numbers who's sum equals 20 and their multiplication equal 93

Are there any? NO!

This means that you have to use the formula:

$\frac{-b±\sqrt{b^{2} - 4ac} }{2a}$

In this case:

a = 1

b = 20

c = 93

$\frac{-(20) plus/minus\sqrt{20^{2} - 4(1)(93)} }{2*1}$

$\frac{-20 plus/minus\sqrt{400 - 372} }{2}$

$\frac{-20 plus/minus\sqrt{28} }{2}$

^^^We must simplify √28

√28 = 2√7

so...

$\frac{-20 plus/minus 2\sqrt{7} }{2}$

simplify further:

$-10 plus/minus\sqrt{7$

-10 + √7

-10 - √7

***plus/minus = ±

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0

2 years ago

What is the quotient in simplified form ? Need help please

Gre4nikov [31]

Answer:

$-\dfrac{4a^{12}b^8}{5}$

Step-by-step explanation:

The applicable rules of exponents are ...

$\dfrac{1}{a^{-b}}=a^b\\\\a^ba^c=a^{b+c}$

Your ratio simplifies to ...

$\dfrac{-8a^8b^{-2}}{10a^{-4}b^{-10}}=-\dfrac{4}{5}a^{8-(-4)}b^{-2-(-10)}\\\\=-\dfrac{4a^{12}b^8}{5}$

_____

Please note that simplifying the constants, -8/10 to -4/5, eliminates half the answer choices. Since exponents are only multiplied when a power is raised to a power, you can pretty much eliminate the second choice as being unreasonable. ((a^b)^c = a^(bc))

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3 years ago