All categories

3 years ago

Whats wrong in this equation ?

1 answer:

6 0

The second step is wrong. What should've been done is to find greatest common factor (gcf) of 1/6 and -2. This is because you cannont add together a number with a variable to a number without a variable. So get the variable by itself by subtracting 1/6 from both sides.

1/5x + 1/6 = -2
___— 1/6_— 1/6
____________

Turn -2 into a fraction and find the gcf of -2 and 6:

1/5x + 1/6 = -2
___— 1/6_— 1/6
____________

1/5x = -2/1 — 1/6 ——> 1/5x = -12/6 — 1/6
1/5x = -13/6

Then divide each side by 1/5 to get the variable by itself; remeber: when dividing a fraction by a fraction, you multiply by the reciprocal.

5/1 • 1/5x = -13/6 • 5/1
x = 65/6

Then, simplify

65/6} 10.83 or 10 83/100

You might be interested in

Assume that the number of messages input to a communication channel in an Exponential distribution with 7 messages arriving in a

NARA [144]

The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

According to the statement

we have given that the an Exponential distribution with 7 messages arriving in a 10 second period and we have to find the probability that more than 3 messages will arrive during a 30-second interval.

So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

And the given information is that :

3 messages will arrive during a 30-second interval.

Then

Probability = P(X=1) + P(X=2) + P(X=3).Then

The probability become according to the exponential distribution:

$P(X=1)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\\P(X=2)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\\P(X=3)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

And then substitute the values in it then

$Probability = \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\ +\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\ + \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

This is the probability.

So, The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

Learn more about probability here

brainly.com/question/24756209

#SPJ4

7 0

2 years ago

Find the slope of each line

ki77a [65]

-4 to +4. Is the answer

5 0

3 years ago

Plz help me with this and u can change the slide too

Nadusha1986 [10]

The 1 slide it is intersecting the second slide is the 4x-y=5 slide 3 is the same and 4th slide is different

4 0

3 years ago

Haseena bought 1 pencil box, 4 pencils and 4 notebooks from a store. She paid Rs. 95 in all. Some ink fell on the bill that she

Rudik [331]

The price of the one notebook will be Rs. 10.6

Let the price of one notebook be x.

If Haseena bought 1 pencil box, 4 pencils and 4 notebooks from a store, with a total of Rs. 95 paid in all, then;

1x + 4x + 4x = 95

9x = 95

x = 95/9

x = 10. 6

Hence the price of the one notebook will be Rs. 10.6

Learn more on ratio here: brainly.com/question/20346769

8 0

3 years ago

Geraldine is picking a four-digit password by using the digits 0 through 9. She can use each digit only once. How many different

BabaBlast [244]

Answer:

5040 different combinations

Step-by-step explanation:

0-9 = 10 numbers

1st digit can be 1 0f 10

2nd digit can be 1 of 9

3rd digit can be 1 of 8

4th digit can be 1 of 7

10×9×8×7=5040

5 0

4 years ago

Read 2 more answers