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ElenaW [278]
3 years ago
13

5. Suppose a system of equations was solved by elimination and the resulting equation was 0 = 3.

Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0

Answer:

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Sketch a generic rectangle to represent the product 3(x+2). Then write an equivalent expression​
abruzzese [7]

Answer:

  3x +6

Step-by-step explanation:

The rectangle representing the product 3(x+2) will have dimensions 3 and (x+2). It can be divided into portions with areas 3·2 = 6, and 3·x = 3x.

An equivalent expression is ...

  3x +6

8 0
2 years ago
6 ice cream cones cost $10. How much will 9 cost?
jek_recluse [69]

Answer:

15 dollars

Step-by-step explanation:

We can write a ratio to solve

6 cones         9 cones

------------   = --------------

10 dollars       x dollars

Using cross products

6*x = 10 *9

6x = 90

Divide each side by 6

6x/6 = 90/6

x = 15

8 0
3 years ago
Solve. 4x−y−2z=−8 −2x+4z=−4 x+2y=6 Enter your answer, in the form (x,y,z), in the boxes in simplest terms. x= y= z=
ladessa [460]

Answer:

(-2, 4, -2)

x=-2, y=4, z=-2.

Step-by-step explanation:

So we have the three equations:

4x-y-2z=-8\\-2x+4z=-4\\x+2y=6

And we want to find the value of each variable.

To solve this system, first look at it and consider what you should try to do.

So we can see that the second and third equations both have an x.

Therefore, we can isolate the variables for the second and third equation and then substitute them into the first equation to make the first equation all xs.

Therefore, let's first isolate the variable in the second and third equation.

Second Equation:

-2x+4z=-4

First, divide everything by -2 to simplify things:

x-2z=2

Subtract x from both sides. The xs on the left cancel:

(x-2z)-x=2-x\\-2z=2-x

Now, divide everything by -2 to isolate the z:

z=-\frac{2-x}{2}

So we've isolated the z variable. Now, do the same to the y variable in the third equation:

x+2y=6

Subtract x from both sides:

2y=6-x

Divide both sides by 2:

y=\frac{6-x}{2}

Now that we've isolated the y and z variables, plug them back into the first equation. Therefore:

4x-y-2z=-8\\4x-(\frac{6-x}{2})-2(-\frac{2-x}{2})=-8

Distribute the third term. The -2s cancel out:

4x-(\frac{6-x}{2})+(2-x)=-8

Since there is still a fraction, multiply everything by 2 to remove it:

2(4x-(\frac{6-x}{2})+(2-x))=2(-8)

Distribute:

8x-(6-x)+2(2-x)=-16\\8x-6+x+4-2x=-16

Combine like terms:

8x+x-2x-6+4=-16\\7x-2=-16

Add 2 to both sides:

7x=-14

Divide both sides by 7:

(7x)/7=(-14)/7\\x=-2

Therefore, x is -2.

Now, plug this back into the second and third simplified equations to get the other values.

Second equation:

z=-\frac{2-x}{2}\\ z=-\frac{2-(-2)}{2}\\z=-\frac{4}{2}\\z=-2

Third equation:

y=\frac{6-x}{2}\\y=\frac{6-(-2)}{2}\\y=\frac{8}{2}\\y=4

Therefore, the solution is (-2, 4, -2)

3 0
3 years ago
Read 2 more answers
Solve : 4(4p+6)=16 find the value of p
inna [77]

Answer:

p=-1/2

Step-by-step explanation:

4(4p+6)=16

4p+6=4

4p=4-6

4p=-2

P=-2/4

p=-1/2

7 0
3 years ago
I just need help in one more ?
Fed [463]
M∠P = 12°
m∠Q = 90°   [A tangent line to a circle is perpendicular to the radius drawn to the tangent point]

m∠O = 90 - 12 = 78°

Answer: x=78°
8 0
3 years ago
Read 2 more answers
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