Answer:
0.5(x)(x + 2) = 24 (A)
x² + 2x – 48 = 0 (D)
x² + (x + 2)² = 100 (E)
Question:
A question related to this found at brainly (ID:4482275) is stated below.
The area of the right triangle shown is 24 square feet. Which equations can be used to find the lengths of the legs of the triangle? Check all that apply.
0.5(x)(x + 2) = 24
x(x + 2) = 24
x2 + 2x – 24 = 0
x2 + 2x – 48 = 0
x2 + (x + 2)2 = 24
Step-by-step explanation:
Find attached the diagram.
Area of triangle = ½ × base × height
= 0.5×b×h
base= x ft
Height = (x+2) ft
Area = 24ft²
24 = 0.5(x)(x+2)
0.5(x)(x + 2) = 24 (A)
The equations that can be used to find the lengths of the legs of the triangle must be equivalent to 0.5(x)(x + 2) = 24
On expanding this: 0.5(x)(x + 2) = 24
0.5(x²+2x) = 24
b) x(x + 2) = 24
x(x + 2) is not equal to 0.5(x²+2x)
c) x² + 2x – 24 = 0
0.5(x²+2x) = 24
0.5x²+x - 24 = 0 is not equal to x²+2x- 24 = 0
d) x² + 2x – 48 = 0
0.5(x)(x + 2) = 24
½(x)(x + 2) = 24
x² + 2x = 2(24)
x² + 2x – 48 = 0
Correct option (D)
x² + (x + 2)² = 100
x² + x² + 4x + 4 = 100
2x² + 4x = 96
2(x² + 2x +48)= 0
x² + 2x +48 = 0 is equal to 0.5(x²+2x) = 24
Correct (E)
Answer:
y + 4 = -3(x -2)
Step-by-step explanation:
A line parallel to y = -3x + 7 also has a slope of -3.
Use the point-slope formula:
y - k = m(x - h)
Inserting the given info, we get:
y + 4 = -3(x -2)
Number of child tickets bought is 20
<h3><u>
Solution:</u></h3>
Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket
cost of each child ticket = 5 dollars
cost of each adult ticket = 8 dollars
Let "c" be the number of child tickets bought
Let "a" be the number of adult tickets bought
Total tickets sold were 110 bringing in 820 dollars
<em>Number of child tickets bought + number of adult tickets bought = 110</em>
c + a = 110 ----- eqn 1
<em><u>Also we can frame a equation as:</u></em>
Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820
5c + 8a = 820 -------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "c" and "a"
From eqn 1,
a = 110 - c ------ eqn 3
Substitute eqn 3 in eqn 2
5c + 8(110 - c) = 820
5c + 880 - 8c = 820
-3c = - 60
c = 20
Therefore from eqn 3,
a = 110 - 20 = 90
a = 90
Therefore number of child tickets bought is 20
Total 7*10^5 trees were planted.
Further explanation:
The product of both quantities will give us the total number of trees planted by the students for the community project.
So,
Given
So, total 7*10^5 trees were planted.
Keywords: Product, exponents
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