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3 years ago

From this given statement, select the definition , property, postulate, or theorem that justifies the prove statement.

1 answer:

5 0

Additive property of equality states that:

if a=b, then a+c = b+c,

that is, if 2 quantities of the same value are added the same quantity, they are again equal.

In our problem a=AD, b=DB, and c= CD=DE

thus a+c=b+c means AD + CD = DE + DE,

by the Addition Property

Answer: Addition Property

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Which inequality is a true statement?

lubasha [3.4K]

9514 1404 393

Answer:

-3 ≤ -1
-3 < -1

Step-by-step explanation:

Negative three is less than (<) negative one, so any statement saying otherwise is incorrect. Correct choices are ...

-3 ≤ -1

-3 < -1

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3 years ago

A box contains 84 chocolates which 63 are dark chocolates. The rest are milk chocolates.what is the ratio of milk chocolates to

serious [3.7K]

Answer:

21:84

Step-by-step explanation:

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3 years ago

Read 2 more answers

The Kamp family has twins, Rob and Rachel. Both Rob and Rachel graduated from college 2 years ago, and each is now earning $50,0

dybincka [34]

Answer:

z-value of rachel = 1.875

z-value of rob = -2

z-value of Rachel is more than that of rob. Thus rob is earning below average and rachel is earning above average.

Step-by-step explanation:

Let's denote the salary of Rob and Rachel per year by X. So, X = $50,000

We are told that;

For Rachel's industry;

Mean salary;μ1 = $35,000

Standard deviation;σ1 = $8,000

For Rob's industry;

Mean salary;μ2 = $60,000

Standard deviation;σ2 = $5,000

Formula for z - value is;

z = (X - μ)/σ

Thus;

z-value for rob is;

z2 = (X - μ2)/σ2

z2 = (50000 - 60000)/5000

z2 = -2

z-value for rachel is;

z1 = (X - μ1)/σ1

z1 = (50000 - 35000)/8000

z1 = 1.875

z-value of Rachel is more than that of rob. Thus rob is earning below average and rachel is earning above average.

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3 years ago

2. CTfastrak bus waiting times are uniformly distributed from zero to 20 minutes. Find the probability that a randomly selected

Juliette [100K]

Answer:

b. 0.25

c. 0.05

d. 0.05

e. 0.25

Step-by-step explanation:

if the waiting time x follows a uniformly distribution from zero to 20, the probability that a passenger waits exactly x minutes P(x) can be calculated as:

$P(x)=\frac{1}{b-a}=\frac{1}{20-0} =0.05$

Where a and b are the limits of the distribution and x is a value between a and b. Additionally the probability that a passenger waits x minutes or less P(X<x) is equal to:

$P(X$

Then, the probability that a randomly selected passenger will wait:

b. Between 5 and 10 minutes.

$P(5$

c. Exactly 7.5922 minutes

$P(7.5922)=0.05$

d. Exactly 5 minutes

$P(5)=0.05$

e. Between 15 and 25 minutes, taking into account that 25 is bigger than 20, the probability that a passenger will wait between 15 and 25 minutes is equal to the probability that a passenger will wait between 15 and 20 minutes. So:

$P(15$

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3 years ago

Statement: If p, then q.

MAVERICK [17]

Answer:

Step-by-step explanation:

I need help

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3 years ago