For me cross multiplying works really well.
Answer:
C7,3=7!( 3!)( 7−3)!= 7! I think tell me if I'm wrong?
Answer:
Step-by-step explanation:
A perfect square trinomial is written as
, where
first term
= square of first term of binomial
second term=
=twice the product of both terms of binomial.
and third term 'c'=square of last term of binomial
Thus to create a perfect square trinomial put 'a' and 'c' a square number
Let a=4 and c=9
The required trinomial will be

![=(2x)^2+2(2x)(3)+3^2\\=(2x+3)^2.......\text{[using pattern}(a+b)^2=a^2+2ab+b^2]\\=(2x+3)(2x+3)](https://tex.z-dn.net/?f=%3D%282x%29%5E2%2B2%282x%29%283%29%2B3%5E2%5C%5C%3D%282x%2B3%29%5E2.......%5Ctext%7B%5Busing%20pattern%7D%28a%2Bb%29%5E2%3Da%5E2%2B2ab%2Bb%5E2%5D%5C%5C%3D%282x%2B3%29%282x%2B3%29)
Answer:

Step-by-step explanation:
Let be
, which can be simplified solely by algebraic means. We proceed to describe all the steps needed for simplification:
1)
Given.
2)
Distributive and associative properties.
3)
/Result