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Nana76 [90]
4 years ago
11

The length of a rectangle is 3 feet more than twice the width. The perimeter is 128 feet. Find the length and width.

Mathematics
2 answers:
pashok25 [27]4 years ago
7 0
Let the width be x feet.

length = 2x + 3 feet

Perimeter = 2x + 2(2x + 3) = 128

6x + 6 = 128

6x = 122

x = 20 1/3

width = 20 1/3   Answer

Length = 2(20 1/3) + 3 =  43 2/3 feet Answer
marishachu [46]4 years ago
6 0
44.6 meters is the length, and the width is 19.3 meters.
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Answer:

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17x²=12x

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Where will her cut be located? Round to the nearest tenth. x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1 A
Arte-miy333 [17]

Answer:

The correct answer is 25.2 in.

Step-by-step explanation:

It is given that number line goes from 0 to 60 which can be used to represent a ribbon of length = 60 inches.

2 inches of the ribbon are frayed so actual length = 58 inches

Please refer to the attached image for the ribbon.

A is at 0

C is at 60

B is at 2

P is the point to divide the remaining ribbon in the ratio 2:3.

Part AB of the ribbon is frayed.

BP: PC = 2:3

Let BP = 2x and PC = 3x

Now, BP + PC = BC = 58 = 2x + 3x = 5x

So,

5x =58\\\Rightarrow x =11.6

BP = 2\times x = 2 \times 11.6 = 23.2\ inches

Location of the Cut = 2 + 23.2 = <em>25.2 inches</em>

<em></em>

Alternatively, we can use the formula directly:

x = \dfrac{m} {m + n } (x_2 - x_1) + x_1

x_1 = 2\\x_2 = 60

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