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2 years ago

Solve x/48 = 5/6 using two different strategies.

1 answer:

5 0

You can do this:
6 * ? = 48, ? = 8, so you multiply the five by 8 too, and you find that x = 40. Another method you can use would just to be to add 5 to the top and 6 to the bottom until the denominators equal each other.

You might be interested in

Who got the answer to this ? <br> (4x^2+6+7)-(-8x^2-2x+6)

Andru [333]

Answer:

12x^2+2x+7

Step-by-step explanation:

Distribute the Negative Sign:

=4x^2+6+7+−1(−8x^2−2x+6)

=4x^2+6+7+−1(−8x^2)+−1(−2x)+(−1)(6)

=4x^2+6+7+8x^2+2x+−6

Combine Like Terms:

=4x^2+6+7+8x^2+2x+−6

=(4x^2+8x^2)+(2x)+(6+7+−6)

=12x^2+2x+7

7 0

3 years ago

There are 38 students. If there are 6 seats at each table, how many tables would be needed for all of the students to be able to

Leto [7]

Answer:

7 tables

Step-by-step explanation:

So if 6 students can fit at each table, you divide 38 by 6. You get 6 1/3 ,but since you can't get 1/3 of a table, you have to get 7

4 0

3 years ago

If a recipe uses 1 1/2 cups of flour and makes 6 servings how many cupes of flour is in one serving

mestny [16]

6/ 1.5 = 4

4 cups of flour in one serving

3 0

3 years ago

mrs. Hudson invested $700 into an account that draws 3% interest, compounded annually. what is the total value of the account af

nadezda [96]

700 x .03 x 20 = 420
420 + 700
1120 is in the account after 20 years

7 0

2 years ago

in a five character password the first two characters must be digits and the last three characters must be letters if no charact

Vilka [71]

Answer:

1,404,000 unique passwords are possible.

Step-by-step explanation:

The order in which the letters and the digits are is important(AB is a different password than BA), which means that the permutations formula is used to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

In this question:

2 digits from a set of 10(there are 10 possible digits, 0-9).

3 characters from a set of 26. So

$P_{10,2}P_{26,3} = \frac{10!}{8!} \times \frac{26!}{23!} = 10*9*26*25*24 = 1404000$

1,404,000 unique passwords are possible.

5 0

2 years ago