Answer:
Step-by-step explanation:
We can use the process of elimination as
5x + 4y = 24
5(x + 7y = 11) —> 5x + 35y = 55
5x + 4y = 24
-(5x + 35y = 55)
—————————
-31y = -31
-31y/-31 = -31/-31
y=1
Answer:
$406.25
Step-by-step explanation:
use an interest calculator :)
Answer:
Step-by-step explanation:
Since the coefficient of x^2 is positive, this quadratic is a parabola in the shape of a U, hence has a minimum.
We want to end up with the form (x-h)^2 + c. Since (x-h)^2>=0, this form shows that the minimum is achieved when x=h.
Completing the square will put the quadratic in the desired form. Note that:
(x-h)^2=x^2-2hx+h^2
Comparing this with the given form, we must have -8=-2h, or h=4. But we are missing h^2=4^2=16. We can add the missing 16 and subtract it elsewhere without changing the quadratic.
x^2-8x+16 + (16-4) = (x-4)^2 + 12
Now we know that at x=4 the quadratic has a minimum and that the minimum is 12.
Point of intersection using substitution (p, j) is (-1, 1).
Given
2p - 6j = -8----------(1)
4p + 12j = 8---------(2)
From equation 1, We can write
2p = -8 + 6j
p = (-8 + 6j)/2
p = -4 + 3j
By using substitution method, substitute p = -4 + 3j in equation 2
4p + 12j = 8
⇒ 4(-4 + 3j) + 12j =8
⇒ 4 × (-4) + 4 × 3j + 12j = 8
⇒ -16 + 12j +12j = 8
⇒ 24j = 8 +16
⇒ 24j = 24
⇒ j = 24/24
⇒ j = 1
then p = -4 +3j
p = -4 + 3(1)
p = -4 + 3
p = -1
Point of intersection (p, j) is (-1, 1).
Find out more information about point of intersection here
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