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3 years ago

Expand or factor each of the following expressions to determine which expressions are equivalent.

Mathematics

1 answer:

IceJOKER [234]3 years ago

5 0

Answer:

1. 9x^2-24xy16y^2

3.9y^2-246y+1681

4. 18x^2+54x-44

Step-by-step explanation:

1. (3x)^2-2*3x*4y+(4y)^2

9x^2-2*3x4y+(4y)^2

9x^2-24xy+(4y)^2

9x^2-24xy+16y^2

Ans: 9x^2-24xy+16y^2 the (*) are times

2. 912+31-20=923

ANS: 13*71

3. 1681-246y+9y^2

9y^2-246y+1681

ANS : 9y^2-246y+1681

4. 3x*(9*2+6x+4)-2(9*2+6x+4)

54x+18^2+12x-2(9*2+6x+4)

54x+18x^2+12x-36-12x-8

54x+18^2+12x-36-12x-8

54x+18x^2-36-8

18x^2+54x-36-8

18x^2+54x-44

Ans: 18x^2+54x-44

5. 3x*3x-3x*4+5*3x-5*4

9x^2-3x*4+5*3x-5*4

9x^2-12x+5*3x-5*4

9x^2-12x+15x-5*4

9x^2-12x+15x-20

ANS: 9x^2+3x-20

6. (31+2)(912-61+4)=28215

ANS : 3^3*5*11*19

7. 9.12-2414+1672

912/100-2414+1672

2^4*3*19/2^2*5^2 -2414+1672

2^4-2*3*19/5^2 -2414+1672

2^2*3*19/5^2 -742

(2^2*3*19)-5^2)742/5^2

(4*3*19)-25*742/5^2

228-18550/5^2

18322/5^2

8. 2713-8

2705

ANS: 5*541

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Free_Kalibri [48]

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4 0

3 years ago

How do I solve this?

zmey [24]

Hey there!!

Multiply both the sides with 4/3.

Then we get

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4 years ago

How many solutions does -(9x+12)=-8x-(x+3) have

Viktor [21]

-(9x+12)=-8x-(x+3)
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4 0

3 years ago

Suppose astronomers built a 50-meter telescope. how much greater would its light-collecting area be than that of the 10-meter ke

drek231 [11]

Answer: Its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.

Step-by-step explanation:

1. To solve this problem you must apply the formula for calculate the area of a circle, which is shown below:

$A=r^{2}\pi$

Where<em> r</em> is the radius of the circle.

2. The diameter of a circle is:

$D=\frac{r}{2}$

Where <em>r</em> is the radius of the circle.

3. Therefore, keeping this on mind, you have that the light-collecting area of a 50-meter keck telescope is:

$A_1=(\frac{50m}{2})^{2}\pi=1963,49m^{2}$

4. And the light-collecting area of a 10-meter keck telescope is:

$A_2=(\frac{10m}{2})^{2}\pi=78.53m^{2}$

5. Divide $A_1$ by $A_2$ , then:

$\frac{1963.49m^{2}}{78.53m^{2}}=25$

6. Therefore, its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.

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4 years ago

ILL MARK BRAINIEST IF YOU DO THIS CORRECTLY!!!

vodomira [7]

1 on top and 4 on the bottom.

6 0

3 years ago