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ser-zykov [4K]
3 years ago
6

BRAINLIEST WILL BE PICKED!

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
6 0
My other answer was was lacking (I also believe I should have furthermore edited it.), therefore I will attempt to explain the steps correctly this time. I don't know what exactly is requested nor what you are learning, but I suspect it would be combinations, factorials, and/or permutations, something along those lines. Firstly I figured out my answer using factorials. 

FROM: F,R,O,M. This obtains 4 letters.

4! (1 x 2 x 3 x 4)= 24 

I am unsure if this is what you are looking for though. I hope this helped a bit.

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What is 30-14x2+8 using pemdas​
uranmaximum [27]

Answer: 10

Step-by-step explanation:

8 0
3 years ago
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How do I solve the square root of 30?
Gre4nikov [31]
There is a way to work it out with a pencil and paper, but that's too complicated
to try and explain with only text, like we have here.

I don't usually recommend this for things that can be done easily on paper ...
but for square roots, your best bet is to use a calculator.

The square root of 30 does not come out even.  It starts out  5.477225...
and it keeps going and never ends.

The negative of  5.477225... is also a square root of 30.  Every number has
two square roots ... the positive and negative of the same number. 
4 0
3 years ago
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Jason is pulling a box across the room. He is pulling with a force of 19 newtons and his arm is making a 30 angle with the horiz
Cerrena [4.2K]

We are to solve for the vertical and horizontal component of the force he is pulling with.

1. The vertical component of Jason's force is 9.5Newtons.

2.The horizontal component of Jason's force is 2.67Newtons.

3. Therefore, the net force in the vertical direction is -12.5Newtons.

4.Therefore, Resultant, R is 72.11

Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The <em>vertical</em> component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the <em>horizontal</em>.

By resolving Jason's force of pull in the <em>horizontal</em> direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the <em>horizontal</em>.

By resolving Jason's force of pull in the <em>vertical</em> direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

Resultant, R = √(68²+24²) = √5200.

Therefore, Resultant, R = 72.11

Read more:

brainly.com/question/24629099

4 0
2 years ago
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~PLEASE HELP ASAP OFFERING 30 POINTS~
Ivenika [448]

The first one is B) september 10 but idk the second one

8 0
3 years ago
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Can i get some help please??? Thanks!!!!
Musya8 [376]

Answer: try 34

Step-by-step explanation:

8 0
3 years ago
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