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3 years ago

Can someone help please asap

Mathematics

1 answer:

ch4aika [34]3 years ago

3 0

Sn = (a1) x (1 - r^n) / (1 - r)

Substituting the known values:

S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27 = 8 24/27 = 8 8/9

You might be interested in

Dado dos ángulos complementarios, uno mide (2x + 10) y el otro (x + 20),

rusak2 [61]

Answer:

El valor de x es igual a 20 o x = 20.

Step-by-step explanation:

Lo primero que se debe saber es que dos ángulos complementarios suman un ángulo recto o 90º.

Supongamos que el valor de un ángulo $\\ \alpha$ y un ángulo $\\ \beta$ valen:

$\\ \alpha = 2x + 10$ [1]

$\\ \beta = x + 20$ [2]

Como la suma de $\\ \alpha + \beta = 90$ [3]

Entonces

$\\ \alpha + \beta = (2x + 10) + (x + 20) = 90$

Sumamos los factores comunes entre si:

$\\ (2x + x) + (10 + 20) = 90$

Para la primera expresión debemos recordar que se suman sólo los coeficientes. Así:

$\\ (2 + 1)x + (10 + 20) = 90$

$\\ 3x + 30 = 90$

Para despejar la incógnita x, debemos tener en cuenta que una igualdad no se altera si se suma, se resta, se multiplica o divide un mismo valor a cada lado de ella. Por esta razón, para despejar 3x, lo primero que podemos hacer es sumar -30 a cada lado de la expresión (lo que es igual a restar 30 a cada lado de la misma). Así tenemos:

$\\ 3x + 30 - 30 = 90 - 30$

$\\ 3x + 0 = 90 - 30$

$\\ 3x = 60$

Ahora dividimos cada miembro de la igualdad entre 3 (o multiplicamos cada lado de la igualdad por $\\ \frac{1}{3}$ ):

$\\ \frac{3}{3}x = \frac{60}{3}$

Como sabemos que:

$\\ \frac{3}{3} = 1$

Entonces:

$\\ 1*x = \frac{60}{3}$

$\\ x = \frac{60}{3}$

$\\ x = 20$

De esta manera, el valor de x es igual a 20 o x = 20.

Lo anterior lo podemos comprobar considerando las ecuaciones [1], [2] y [3]. Así tenemos que:

$\\ \alpha = 2x + 10$ [1]

Sustituimos x por el valor de 20:

$\\ \alpha = 2*20 + 10 = 40 + 10 = 50$

$\\ \beta = x + 20$ [2]

Hacemos lo mismo para [2]:

$\\ \beta = 20 + 20$

$\\ \beta = 40$

De esta manera:

$\\ \alpha + \beta = 90$ [3]

$\\ 50 + 40 = 90$

4 0

3 years ago

twice the number of donuts was only 6 less than 24 times the number of cream puffs. 10 times the number of cream puffs was only

Karolina [17]

donuts and cream puffs were 45 & 4 respectively !

Step-by-step explanation:

Here we have , twice the number of donuts was only 6 less than 24 times the number of cream puffs. 10 times the number of cream puffs was only 5 less than the number of donuts We need to find how many donuts and cream puffs were there . Let's find out:

Let number of donuts and cream puffs are x & y respectively ! So ,

twice the number of donuts was only 6 less than 24 times the number of cream puffs

According to this statement equation is :

⇒ $2x=24y-6$

⇒ $x=12y-3$ ................(1)

10 times the number of cream puffs was only 5 less than the number of donuts

According to this statement equation is :

⇒ $10y= x-5$

⇒ $x=10y+5$ ................(2)

Equation (1) & (2) :

⇒ $12y-3=10y+5$

⇒ $2y=8$

⇒ $y=4$

Putting $y=4$ in $x=12y-3$ :

⇒ $x = 12(4)-3$

⇒ $x = 45$

Therefore , donuts and cream puffs were 45 & 4 respectively !

7 0

3 years ago

PLEASE ANSWER FAST WILL DO BRAINLIESTThe coordinate grid shows points A through K. What point is a solution to the system of ine

Alja [10]

Answer: points B (4,7) and I (9,3)

If the inequalities are

y > −2x + 10 and y> (½)x -2

Step-by-step explanation: If I interpreted the inequalities correctly, the attached graph shows them. It is possible that you meant y > 1/(2x-2) for the second inequality. If so, we start over!

You can test the values for all the points, but it appears that (4,7) and (9,3) both work.

The other coordinates appear to be outside the solution -- the dark-shaded area.

I hope this is your Brainliest answer. It was a lot of work!