1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Debora [2.8K]
4 years ago
10

If it takes 30 seconds for a reactant concentration to decrease from 1.0 M to 0.5 M in a first-order chemical reaction, then wha

t is the rate constant for the reaction? A. 0.033 s^–1 B. 0.046 s^–1 C. 0.023 s^–1 D. 43 s^–1
Chemistry
1 answer:
zhenek [66]4 years ago
4 0
The answer is A. For a first-order chemical reaction, the rate constant k has a relationship with concentration C as follow: dC/dT=k*C. So in this reaction, (1-0.5)/30=k*0.5. So k=0.033
You might be interested in
Jack an investigator wants to prove that a certain suspect was present at the crime scene when the crime was committed. What kin
grin007 [14]

Answer:

eye witnesses, dna, fingerprints, hair, time stamped photos/ videos

Explanation:

:)

5 0
3 years ago
Consider an ice cube with a volume of 0.50 cup. (1 cup = 240.0 mL, density of ice = 0.9167 g/mL). How many water molecules (mola
stealth61 [152]

Answer:

3.86x10^24 molecules

Explanation:

From the question given, the following data were obtained:

Volume of ice = 0.5cup

1 cup = 240mL

0.5cup = 0.5 x 240 = 120mL

Density of ice = 0.9167 g/mL

molar mass of water = 18.015g/mol

First let us calculate the mass of ice. This is illustrated below:

Density = Mass /volume

Mass = Density x volume

Mass = 0.9167 x 120

Mass of ice = 110.004g = Mass of water

From Avogadro's hypothesis, we understood that 1mole of any substance contains 6.02x10^23 molecules. This means that 1mole of water will also contain 6.02x10^23 molecules.

1mole of water = 18.015g

If 1 mole (18.015g) contains 6.02x10^23 molecules,

Therefore, 110.004g of water will contain = (110.004x6.02x10^23)/18.015 = 3.86x10^24 molecules

3 0
3 years ago
Identify the precipitate (if any) that forms when NaCH3COO (also written as NaC2H3O2) and HCl are mixed
babymother [125]
For this item, we will have a double-replacement reaction. This means that the compounds will exchange elements. The balanced chemical reaction is shown below.
                   NaCH3COO + HCl --> NaCl + CH3COOH
So, what are formed in the reaction is the salt NaCl and the carboxylic acid, acetic acid. Hence, the precipitate formed is the salt NaCl. 
5 0
3 years ago
Read 2 more answers
Aluminum foil, cast iron pans, copper pipes, graphite, and sea water can be classified as
Korolek [52]

answer

C) is the answer ⟵(๑¯◡¯๑)

3 0
3 years ago
Read 2 more answers
In the combination reaction between oxygen and magnesium, 12.25 grams of
stepan [7]

Answer:

2 Mg + O2 → 2 MgO b. From the reaction in the previous question, how many moles of oxygen are needed to completely react with 12 moles of magnesium.

Explanation:

hope this helps

4 0
3 years ago
Other questions:
  • When there is unequal sharing between two atoms of the electrons in a bond, which type of bond is it?
    9·2 answers
  • Which of these is something whose construction MOST LIKELY would be determined by the government? A) An airport B) A golf club C
    7·2 answers
  • CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7
    12·1 answer
  • A substance absorbed 895 J and caused its temperature to increase by 10 ºC. If the substance has a mass of 27.9 g, what is the s
    10·2 answers
  • Convert 12.0 g of FeO into moles.
    14·1 answer
  • How many moles are equal to 157.8g of CaCl2?
    5·1 answer
  • Help me please!!!!!!!
    13·1 answer
  • 26.5 g of a solution with a density of 7.48 g/mL
    15·1 answer
  • What do cones and flowers have in common
    12·2 answers
  • Esters, RCOOR9, are formed by the reaction of carboxylic acids, RCOOH, and alcohols, R9OH, where R and R9 are hydrocarbon groups
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!