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IRINA_888 [86]
3 years ago
8

Identify the precipitate (if any) that forms when NaCH3COO (also written as NaC2H3O2) and HCl are mixed

Chemistry
2 answers:
babymother [125]3 years ago
5 0
For this item, we will have a double-replacement reaction. This means that the compounds will exchange elements. The balanced chemical reaction is shown below.
                   NaCH3COO + HCl --> NaCl + CH3COOH
So, what are formed in the reaction is the salt NaCl and the carboxylic acid, acetic acid. Hence, the precipitate formed is the salt NaCl. 
shepuryov [24]3 years ago
5 0

No precipitate is formed by reaction of {\textbf{NaCH}\mathbf{_3}\textbf{COO}} and HCl.

Further Explanation:

Precipitation reactions:

Such reactions involve formation of insoluble salt when solutions of soluble salts combine with each other. This insoluble salt is termed as precipitate. Due to formation of precipitates, these reactions are known as precipitation reactions. These reactions are essential tool in determination of different ions existing in particular solutions.

\text{NaCH}_3\text{COO} is sodium salt of acetic acid and is therefore weak acid. But, on the other hand, HCl is a strong acid and is capable to displace sodium from sodium acetate salt. As a result, acetic acid and sodium chloride are formed.

Reaction between \text{NaCH}_3\text{COO} and HCl occurs as follows:

\text{NaCH}_3\text{COO}+\text{HCl}\rightarrow\text{CH}_3\text{COOH}+\text{NaCl}

In this reaction, one mole of \text{NaCH}_3\text{COO} reacts with one mole of HCl and one mole of \text{CH}_3\text{COOH} and one mole of NaCl are produced. Both products are soluble in water. Since both of the products of this reaction are water soluble, no precipitate can be formed by reaction of \text{NaCH}_3\text{COO} and HCl.

Learn more:

1. Balanced chemical equation: brainly.com/question/1405182

2. Oxidation and reduction reaction: brainly.com/question/2973661

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Chemical reactions and equations

Keywords: NaCH3COO, HCl, CH3COOH, NaCl, precipitate, soluble salts, insoluble salts, no precipitate, salt, weak acid, strong acid, sodium, sodium acetate salt, reaction, acetic acid, sodium chloride, ions, solutions, water soluble.

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I assume you meant \text{K}_{2}\text{SO}_{4}.

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Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to firstly draw the structure of the reactant, pent-1-yne:

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