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IRINA_888 [86]
3 years ago
8

Identify the precipitate (if any) that forms when NaCH3COO (also written as NaC2H3O2) and HCl are mixed

Chemistry
2 answers:
babymother [125]3 years ago
5 0
For this item, we will have a double-replacement reaction. This means that the compounds will exchange elements. The balanced chemical reaction is shown below.
                   NaCH3COO + HCl --> NaCl + CH3COOH
So, what are formed in the reaction is the salt NaCl and the carboxylic acid, acetic acid. Hence, the precipitate formed is the salt NaCl. 
shepuryov [24]3 years ago
5 0

No precipitate is formed by reaction of {\textbf{NaCH}\mathbf{_3}\textbf{COO}} and HCl.

Further Explanation:

Precipitation reactions:

Such reactions involve formation of insoluble salt when solutions of soluble salts combine with each other. This insoluble salt is termed as precipitate. Due to formation of precipitates, these reactions are known as precipitation reactions. These reactions are essential tool in determination of different ions existing in particular solutions.

\text{NaCH}_3\text{COO} is sodium salt of acetic acid and is therefore weak acid. But, on the other hand, HCl is a strong acid and is capable to displace sodium from sodium acetate salt. As a result, acetic acid and sodium chloride are formed.

Reaction between \text{NaCH}_3\text{COO} and HCl occurs as follows:

\text{NaCH}_3\text{COO}+\text{HCl}\rightarrow\text{CH}_3\text{COOH}+\text{NaCl}

In this reaction, one mole of \text{NaCH}_3\text{COO} reacts with one mole of HCl and one mole of \text{CH}_3\text{COOH} and one mole of NaCl are produced. Both products are soluble in water. Since both of the products of this reaction are water soluble, no precipitate can be formed by reaction of \text{NaCH}_3\text{COO} and HCl.

Learn more:

1. Balanced chemical equation: brainly.com/question/1405182

2. Oxidation and reduction reaction: brainly.com/question/2973661

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Chemical reactions and equations

Keywords: NaCH3COO, HCl, CH3COOH, NaCl, precipitate, soluble salts, insoluble salts, no precipitate, salt, weak acid, strong acid, sodium, sodium acetate salt, reaction, acetic acid, sodium chloride, ions, solutions, water soluble.

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For the reaction Na2CO3+Ca(NO3)2⟶CaCO3+2NaNO3 how many grams of calcium carbonate, CaCO3, are produced from 79.3 g of sodium car
Alexus [3.1K]

Answer:

74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.

Explanation:

The balanced reaction is:

Na₂CO₃ + Ca(NO₃)₂ ⟶ CaCO₃ + 2 NaNO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • Ca(NO₃)₂: 1 mole
  • CaCO₃: 1 mole
  • NaNO₃: 2 mole

Being the molar mass of the compounds:

  • Na₂CO₃: 106 g/mole
  • Ca(NO₃)₂: 164 g/mole  
  • CaCO₃: 100 g/mole
  • NaNO₃: 85 g/mole

then by stoichiometry the following quantities of mass participate in the reaction:

  • Na₂CO₃: 1 mole* 106 g/mole= 106 g
  • Ca(NO₃)₂: 1 mole* 164 g/mole= 164 g
  • CaCO₃: 1 mole* 100 g/mole= 100 g
  • NaNO₃: 2 mole* 85 g/mole= 170 g

You can apply the following rule of three: if by stoichiometry 106 grams of Na₂CO₃ produce 100 grams of  CaCO₃, 79.3 grams of Na₂CO₃ produce how much mass of  CaCO₃?

mass of CaCO_{3} =\frac{79.3 grams of Na_{2} CO_{3} *100 grams of of CaCO_{3}}{106 grams of Na_{2} CO_{3}}

mass of CaCO₃= 74.81 grams

<u><em>74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.</em></u>

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