Hint: A mole is the entity that denotes 6.022×1023 particles.
Ability to move up through thin tunes because a physical property is something you can observe about the matter. Out of all of them this one does not fit.
Answer:
i.e. mass of 1 mole of glucose, C6H12O6 = (6 × 12.01 + 12 × 1.01 + 6 × 16.00) g = 180.18 g (using atomic weight data to 2 decimals) 1 mole of carbon atoms weighs 12.01 g and there are 6 moles of C atoms in 1 mole of glucose, so the mass of carbon in 1 mole of glucose = 6 × 12.01 g = 72.06 g.
The values of the changes are
ΔH = 46.44kJ
Δu = 43.34Kj
ΔS = 126.6 J/K
<h3>How to find change in H</h3>
= 1 mol + 75.3 (100 + 273) - 25 + 273 + 1 * 40.79
= 5.6475 + 40.79
= 46.44kJ
<h3>How to find change in S</h3>
1 mol + 75.3 x ln 373/298 + 1 mol x 40.79
= 0.1263
ΔS = 126.6 J/K
<h3>How to find the change in U</h3>
46.44 - 0.00831 * 373
= 43.34Kj
Read more on molar heat here:
brainly.com/question/13439286
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