To find the interquartile range, you will list the data that is presented in the stem and leaf plot.
Find the median of the data (30.5)
Find the median of the lower half and the median of the upper half.
Subtract these two values.
The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
27.5 40.5
40.5-27.5 = 13
The interquartile range is 13.
I believe it is GCF because 9v^3 can be factored out of the expression, becoming:
9v^3 (4 - 3v^2)
9v^3 (-3v^2 + 4)
The quadratic in parentheses can be solved, but with the quadratic equation or by graphing.
Answer:
12x12
Step-by-step explanation:
12x12=144
Answer:
-11
Step-by-step explanation:
First we plug -2 in for c
4(-2)-3=-8-3=-11
We get tne n-th term with: tn=1/3tn-1
We know that the first term is t1=81, so 81=1/3t*1-1
81=1/3t-1
82=1/3t
82*3t=1
3t=1/82
t=1/82*3=1/246
The second term is: 1/
2*(1/246)*2)-1
We get the third term by replacing n with 3 and so on...
