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mihalych1998 [28]
3 years ago
11

Max p=3x+2y subject to 5x+y<16 2x+3y<22 x>0 y>0

Mathematics
1 answer:
garri49 [273]3 years ago
3 0

Answer:For all the corner points, the maximum is at point (1, 3)

From the graph of the constraints, the corner points of the feasibility region are (0, 0), (0, 10/3), (1, 3), (2, 0)

For (0, 0): p = 0 + 2(0) = 0

For (0, 10/3): p = 0 + 2(10/3) = 20/3 = 6.67

For (1, 3): p = 1 + 2(3) = 1 + 6 = 7

For (2, 0): p = 2 + 2(0) = 2

Therefore, solution = (1, 3)

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