Answer:
I would pick A B and D to be my answer
Answer:
The time elapsed is 0.017224 s
Solution:
As per the question:
Analog signal to digital bit stream conversion by Host A =64 kbps
Byte packets obtained by Host A = 56 bytes
Rate of transmission = 2 Mbps
Propagation delay = 10 ms = 0.01 s
Now,
Considering the packets' first bit, as its transmission is only after the generation of all the bits in the packet.
Time taken to generate and convert all the bits into digital signal is given by;
t = 
t =
(Since, 1 byte = 8 bits)
t = 7 ms = 0.007 s
Time Required for transmission of the packet, t':


Now, the time elapse between the bit creation and its decoding is given by:
t + t' + propagation delay= 0.007 +
+ 0.01= 0.017224 s
Answer:
Some key points to remember, when handling the linked list are as follow:
- Linked list is the linear data structure in which each of the elements contain separate object.
- Linked list components are not store in a contiguous location.
- In the linked list the elements or components are basically use the pointers for linked with another elements.
- The last node of the linked list must contain null value.
- In the linked list, the allocation of the memory is equal to upper node limit.
D)Exhaustion
Hope this helps